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NEET UG 2026 » NEET UG Study Material » Chemistry » Charle’s law
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Charle’s law

Charles’ law asserts that the volume of a gas is precisely proportional to the absolute temperature under constant pressure .

Table of Content
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A fully inflated balloon is placed inside a container containing liquid nitrogen (at a temperature of -196 0C) in a famous scientific experiment. The balloon shrinks to around 1/1000th of its original size. Similarly, keeping an inflated balloon in the fridge causes it to shrink significantly. If the balloon is safely removed from the container or the fridge is allowed to warm itself to room temperature gradually, it will restore its original size; it has shrunk due to the chilling of liquid nitrogen. This is one of the most straightforward experiments for demonstrating the effects of temperature on gasses.

The Law’s Discovery and Naming

The rule was named after the French mathematician, physicist, inventor, and balloonist Jacques Alexandre César Charles. He made history by being the first person to launch a manned hydrogen-filled gas balloon. Natural philosopher Joseph Louis Gay-Lussac wrote a paper outlining how gases expand when heated just a few days after the first human-crewed hot air balloon flight in 1802. He attributed it to Jacques Charles’s unpublished work from the 1780s. In honor of Charles, Gay-Lussac titled the statute ‘Charles Law.’

In 1787, Charles experimented with filling five identical containers with various gasses. After that, he raised the temperature of the containers to 80 degrees Celsius. He then saw that all gases had grown in volume by the same amount. Gay-Lussac mentioned this experiment in his paper from 1802. Charles deduced that the volume of gas grows linearly with the absolute temperature of that gas under constant pressure and named it as Charles law.

What is Charles’ Law, exactly?

Charles’ Law, often known as the law of volumes, describes how a gas expands as the temperature rises. On the other hand, a reduction in temperature will result in a decrease in volume.

When comparing a material under two distinct situations, we may write the following from the previous statement:

V2/V1= T2/T1

OR

V1.T2=V2.T1

This Charles’ law equation shows that when the gas’s absolute temperature rises, the volume of the gas rises in proportion.

To put it another way, Charle’s law is a variant of the ideal gas law. The law applies to ideal gases kept at constant pressure but has varying temperatures and volumes.

Everyday Examples of Charles’ Law

Here are some instances that can help you comprehend Charle’s law quickly.

The only need to check the pressure in your automobile tires while going outside on chilly days is for this reason. When you take a basketball outside on the ground in the winter, the ball shrinks as the temperature drops. This is true of any inflated item, which is why checking the pressure in your automobile tires as the temperature lowers is a brilliant experiment idea.

Charles’ law governs the operation of pop-up turkey thermometers. An overfilled tube placed in a pool might cause bloat and rupture, while the gas inside the thermometer increases as the turkey cooks. Another prominent application is the operation of an automobile engine.

The formula for Charles’ Law

The formula for stating Charles’ Law is as follows:

VI /TI=VF /TF

Where VI denotes the initial volume

VF stands for the final volume.

TI denotes the initial absolute temperature.

TF stands for final absolute temperature.

It’s important to understand that these are absolute temperatures measured in Kelvin, not in degrees Fahrenheit or Celsius.

Charles’ Law’s Derivation

We know that, according to Charles’ law, the volume of a certain amount of dry gas is precisely proportional to absolute temperature at constant pressure. The following is a representation of the statement.

V∝T

We can use the constant k to equal V and T because they are both directly changing.

V/T = constant = k

In this case, the value of k is determined by the gas’s pressure, volume, and unit of measurement.

V*T=k——-(1)

Consider V1 and T1 as the starting volume and temperature of an ideal gas, respectively.

Charles law equation (1) can therefore be written as

V1/T1=k——-(2)

After that, we’ll alter the gas’s temperature to T2. Alternatively, if the volume switches to V2, we will write.

V2/T2=k——–(3)

Equating the two equations above (equations 2 and 3) yields

V1/T1=V2/T2

OR

V1T2=V2T1

You’re not aware that heating a fixed amount of gas, that is, raising the temperature, also increases the volume. Similarly, as the temperature is reduced, the volume of the gas is reduced. For every unit degree increase in temperature, the volume increases by 1/273 of its initial volume at 0 degrees centigrade.

For situations using Charles’ law, it is critical to remember that the temperature unit must be in Kelvin, not Celcius or Fahrenheit, as previously stated. The absolute temperature scale is also known as the Kelvin temperature scale. To convert a temperature from Celsius to Kelvin, multiply the temperature by 273 in the Celsius scale.

The volume (V) of gas is precisely proportional to its temperature (T), which must be in Kelvin, according to Charles’ Law.

A change in temperature of one Kelvin unit equals a change in temperature of one Celsius degree. Always remember that 0 degrees Kelvin equals -273 degrees Fahrenheit, or “Absolute Zero.”

When the gas has the same mass and pressure, its density is inversely proportional to its temperature in Kelvin.

Application of Charles Law in Real Life

This law has several applications in everyday life. On the other hand, the balloon regains its shape when placed in a warm environment. What causes this to happen- If you’ve ever been outside on a cold day, you’ve probably observed that the balloon crumbles? This occurs because the volume reduces when the temperature drops on a chilly day. Now, according to Charle’s Law, the temperature rises as soon as you enter a heated room; as the temperature rises, the volume rises as well. As a result, the balloon returns to its former shape.

2- Our kitchens are no exception to Charle’s Law. If you’ve ever tried your hand at baking, you’re probably familiar with the most popular ingredient in the process: yeast. Baking yeast is commonly used to generate fluffy baked items. The release of carbon dioxide bubbles is caused by yeast. When the temperature rises, the carbon dioxide bubbles expand, acting as a leavening agent, causing the bread items to puff up. With a higher temperature, the carbon dioxide bubbles will expand even more.

3- You may have been curious about how a hot air balloon works. Temperature and volume are precisely proportional to each other, according to Charle’s Law. You may have been curious about how a hot air balloon works. When you heat a gas, it expands. As the gas expands, the density of the gas decreases, and the balloon rises into the air. Warm air is less dense than cold air, which is lighter. Warm air also has less mass per unit volume.

Charle’s rule also governs the operation of the Pop-Up Turkey Timer (Thermometer). Let’s look at how! If you recall, Charle’s law says that gasses expand when heated. The Pop-Up Turkey Timer works on the same concept. The turkey’s thermometer (or timer) is inserted inside. The gas inside the thermometer expands as the temperature rises, so it’s time to remove the turkey from the oven.

Solved Problems 

  1. A gas sample has a volume of 20.8L and a temperature of -67 degrees Celsius at the start. If the volume of the gas is 11.0L, what would the temperature be?

Solution:

According to the question,

V1= 20.8L

T1=-67 degree celsius=206K

T2=?

V2=11.0L

According to Charles’ law

V1/T1=V2/T2

20.8/206=11/T2

T2= 11*206/20.8

=108.94 K 

If V1 is the 3.60L, T1=255K, T2=308.43K, then find the value of V2?

According to the question V2=?

As we are aware of Charles’ law

V1/T1=V2/T2

3.60/255=V2/308.43

V2= 4.35L

faq

Frequently asked questions

Get answers to the most common queries related to the NEET UG Examination Preparation.

At 0 degrees Celsius and 780 millimeters of mercury, a gas occupies a volume of 400cm3. At 80 degrees Celsius and 780 millimeters of mercury, how many liters of volume will the gas occupy?

Ans. According to the question, V1=400cm3 T1=0 degree Celsius= 0+273=273K T2=80 DEGREE CELCIUS=80+273=353K V1=400cm3 T1=0 degree C...Read full

A sample of gas has an initial volume of 30.8L and a temperature of -67 degrees Celsius when it is first collected. If the volume of the gas is 21.0L, what will be the temperature of the gas?

Ans. The answer is: V1= 30.8L T1=-67 degrees Celsius=206K T2= according to the question. V2=21.0L In accordance with...Read full

At 0 degrees Celsius and 760 millimeters of mercury, a gas occupies 221 cubic centimeters of space. What will the volume be at 100 degrees Celsius?

Ans. Given that the pressure is constant and the mass of the gas does not change, we can apply Charle’s law to this situatio...Read full

Give an everyday example of Charle's Law.

Ans. The ball shrinks when you play basketball outside in the ground during the winter because the temperature drops as the season...Read full

How Charle's Law is represented in a graph?

Ans. When the pressure remains constant, the graph between V and T is referred to as an isobar (also known as an isoplestics), and...Read full

Ans. According to the question, V1=400cm3 T1=0 degree Celsius= 0+273=273K T2=80 DEGREE CELCIUS=80+273=353K V1=400cm3 T1=0 degree Celsius= 0+273=273K

You’ll need to track down the V2.

Only the temperature is changing in this situation; the pressure remains constant.

In accordance with Charle’s law, V1/T1=V2/T2

When we put the above values into the Charle’s law, we get 400/273=V2/353 V2=400*353/273 V2=517.21CM3 When we put the above values into the Charle’s law, we get 400/273=V2/353

Considering that one cubic centimeter equals 0.001 liters, the volume of 517.21 cubic centimeters equals 517.21*10-3=0.517 liters.

Ans. The answer is: V1= 30.8L T1=-67 degrees Celsius=206K T2= according to the question.

V2=21.0L

In accordance with Charle’s law,

V1/T1=V2/T2 30.8/67=21/T2 T2=21*67/30.8 =46.90C V1/T1=V2/T2 30.8/67=21/T2 T2=21*67/30.8 =46.90C

How do you calculate the value of V2 if V1 is

3.60L, T1 is 255K, and T2 is 102K?

According to the answer to the question V2=?

We are all familiar with the Charle’s law, which states that V1/T1=V2/T2 3.60/255=V2/102 V2= 1.44L.

Ans. Given that the pressure is constant and the mass of the gas does not change, we can apply Charle’s law to this situation without difficulty.

Because the temperature in the question is given in degrees Celsius, it must be converted to absolute temperature, which is measured in degrees Kelvin, in order to apply the formula:

V1=221cm3;T1=273(0+273);T2=373K(100+273)

Now, the values that have been provided can be entered into the formula to obtain the final volume.

VI /TI=VF /TF\s221/273=VF/373

Changing the order of the equation above allows us to obtain the final volume.

VF=(221)*(373)/273K\sVF=302cm3

Ans. The ball shrinks when you play basketball outside in the ground during the winter because the temperature drops as the season progresses. This is the only reason why it is critical to check the pressure in your car tyres when you are driving outside on cold days. Any inflated object suffers from the same problem, which explains why checking the pressure in your car tyres when the temperature drops is a good idea.

Ans. When the pressure remains constant, the graph between V and T is referred to as an isobar (also known as an isoplestics), and it always produces a straight line. A straight line at – 273.15°C is drawn on a plot of V versus T (°C) when the pressure is constant. The lowest temperature that can be reached is -273.15 degrees Celsius.

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