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Previous years GATE problems based on Two Wattmeter Method (Part 1)
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In this lesson I've discussed previous years GATE problems based on Two Wattmeter Method.

Pawan Chandani is teaching live on Unacademy Plus

Pawan Chandani
Faculty of GATE/ESE (Electrical Engineering) , Also a YouTuber and teaches Electrical Eng. subjects on YouTube | Jony Ive Award Winner

U
Unacademy user
Kindly please start the Course on LIC AAO Exam 2019 as the notification has been out
Mona Choudhary
8 months ago
Ok I will start now...
TUSHAR GUPTA
8 months ago
Thanks!!!
@8:29 i think fraction will be 8/13.please clarify.
SS
@6.25 sir why we considered (-168.4) instead of 168.4 in pf calculation? please sir explain
Pawan Chandani
a year ago
because we have to find phase difference that's why we take -168.4 instead of 168.4
Q10 I think network is star connected but you are saying it is delta connected? its confusing please clear it
Pawan Chandani
a year ago
No, it's not star connected it's delta connected load....To check whether the load is star connected or delta connected we have to check line voltage, line current, phase voltage and phase current....in this question you can check here phase voltage and line voltage are same...that happens in case of delta connection. in star connection line voltage and phase voltage are not same.
Nandan kumar
a year ago
ok sir thank you
Q10 if we see voltage across B phase is sum of voltage drop across R1 and X2 but in corresponding line voltage Vby voltage is sum of voltage drop across R1 X2 and X1. how can it be same
Pawan Chandani
a year ago
Why you are thinking like that simply line voltage is given so take it as reference and remaining lines voltags are according to phasor angle. Why you are considering the voltage drop across R1 and X1.I think you should watch it again.
  1. Previous Year GATE problems based on Two Wattmeter Method By- Pawan Chandani


  2. Q 10. A Symmetrical 400V, 30 supply is connected to the network shown in fig. The phase sequence is RYB. Find the reading of the wattmeter R1-30 , X1 =501% = 40 x2


  3. Q 10. A Symmetrical 400V, 30 supply is connected to the network shown in fig. The phase sequence is RYB. Find the reading of the wattmeter R1-30 , 501LX,-40 y8 Pc RB RY BR 180 phase shift = 40 -60 U


  4. RY 8<90- = 50 L-60 BR R B 4002-60 30 i40 R8 8 2-113.13 RB RY RB = 3.2 L 168, 4


  5. PC Pc Cc . . 400 x 3.2 cos (-12D'-'68.4 )


  6. Q 11. Two wattmeter, which are connected to measure the total power on a 3-0 system supplying a balanced load, read 10.5 kW and -2.5 kW respectively. The total power and the power factor respectively are 8o)


  7. Q 11. Two wattmeter, which are connected to measure the total power on a 3-0 system supplying a balanced load, read 10.5 kW and -2.5 kW respectively. The total power and the power factor respectively are 10.5-2.5 13 2 13 tan-1(N3 70.44 = PE= = cos (70.44 ) = 0.334


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