Multiplication Table of 81 represents the results of multiplying 81 by various whole or natural numbers. The multiplication table of 81 is the repeated addition of 81. For example, on adding 81 four times – 81 + 81 + 81 + 81 = 364. The Table of 81 from numbers 1 to 20 are listed below.
Table of 81 up to 10
81 × 1 = 81 | 81 × 6 = 486 |
81 × 2 = 162 | 81 × 7 = 567 |
81 × 3 = 243 | 81 × 8 = 648 |
81 × 4 = 324 | 81 × 9 = 729 |
81 × 5 = 405 | 81 × 10 = 810 |
Table of 81 up to 20
81 × 11 = 891 | 81 × 16 = 1296 |
81 × 12 = 972 | 81 × 17 = 1377 |
81 × 13 = 1053 | 81 × 18 = 1458 |
81 × 14 = 1134 | 81 × 19 = 1539 |
81 × 15 = 1215 | 81 × 20 = 1620 |
Tips for Memorising the Table of 81.
- One of the most common tricks students use is writing down the multiplication table of 81 from 1 to 20. Example: One-time eighty-one is 81, Two times eighty-one is 162, Three times eighty-one is 243, and so on.
- The second easy trick is skip counting, which is the practice of counting forward from 0. We repeatedly add the same number to the last number to skip counting. For example, here, we will count, adding 0 to 81. So, 0 + 81 = 81 , 81 + 81 = 162, 162 + 81 = 243 and so on.
- Eighty-one can also be written as 80 + 1. We know the trick for the multiplication table of 80, i.e., writing down the same multiplication table of 8 with 0 as its last digit. After getting the multiples of 81, we can add the multiplication table of 1 parallel to it to obtain the Table of 81. Take a look at the Table shown below
Table of 8 | Adding 0 as last digit | Table of 1 | ||
8 x 1 = 8 | 80 | 1 x 1 = 1 | + | 81 |
8 x 2 = 16 | 160 | 1 x 2 = 2 | + | 162 |
8 x 3 = 24 | 240 | 1 x 3 = 3 | + | 243 |
8 x 4 = 36 | 360 | 1 x 4= 4 | + | 324 |
Solved Examples
1)A factory manufactures 81 chocolates in one batch. How many chocolates are manufactured in a day if the entire batches completed are 11?
Solution:
Number of chocolates manufactured in 81 batches = 81
Number of chocolates manufactured in 11 batches = number of chocolates manufactured in 1 batch x 11
So, 81 x 11 = 891.
Therefore, the number of chocolates manufactured in 11 batches is 891.
2) 81 flights depart in one day from an airport. Find how many total flights will leave in two weeks.
Solution:
Number of flights departed daily = 81
Number of flights departed in two weeks = number of flights departed daily x 14 days
=> 81 x 14 = 1134
A total of 1134 flights depart from the airport in two weeks.
3)Ramesh sells 1 kg of apples for Rs 81. Suppose a customer bought 12 kg apples. Find the amount to be paid.
Solution:
Cost of 1 kg apples = Rs 81
Cost of 12 kg apples = Cost of 1 kg apples x 12
So, 81 x 12 days = 972.
Therefore, the amount paid by the customer to Ramesh for 12 kg apples is Rs 972.
4) What is the value of six times 81 divided by 9 minus 18 plus 20?
Six times 81 is 6 x 81= 486
Now we have to divide 648 by 9 minus 18 plus 20.
So, 4869 -18 + 20 = 54 – 2
=> 54 – 2
= 52.
Therefore, the value of six times 81 divided by 9 minus 18 plus 20 is 70.