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E.M.F. and Internal Resistance of a Cell

E.M.F. and Internal Resistance of a Cell depend on each other. Here, we will understand the relationship and its effects on a circuit.

E.M.F. of a cell

Maximum potential difference between two electrodes of a cell is known as E.M.F. (Electromotive force).

Dynamic Induced E.M.F. is generated when a current-carrying conductor cuts the magnetic flux using relative motion. The magnitude of induced e.m.f is directly proportional to the negative rate of variation of the magnetic flux attached with the circuit.

As chemical energy is turned into electrical energy, the E.M.F. of a cell decreases as current is extracted from it. The correct way to measure is to do it in such a way that no current is passed from the cell in order to get accurate E.M.F. Since, this isn’t practical in practise, the measurement is done under certain conditions when the current passed from the cell is so little that it goes almost undetectable. 

Volts are the unit of measurement. A potentiometer circuit is the type of electrical circuit he employed.

Figure 1

An anode is an electrode that undergoes oxidation, while a cathode is an electrode that undergoes reduction. Figure 1 depicts a simple potentiometer circuit. A metal develops a potential in relation to the electrolyte when it comes into contact with its own ion solution. AB is a wire with a constant resistance. Through a variable resistance, R, the wire’s ends A and B are attached to two electrodes of a lead storage battery C. There is a progressive drop in potential through the wire AB that is proportional to its length. One of the cell’s electrodes, E, whose e.m.f measurement is to be done, is connected to A via a galvanometer, G.The other electrode is connected to AB by a sliding contact D via a key, K. The E.M.F. of the cell is the potential difference between both the anode and cathode.

The contact D is moved along the wire after pressing the key K to the point that there is no deviation of the galvanometer, thus indicating no current flow.  At this point, the potential drop across the wire AB from point A to D is equivalent to the cell E’s potential. When the cell E is replaced by a standard cell with a highly precise potential, a new position of the contact, D’, is discovered when the flow of current through the galvanometer is zero. At this position –

Length of the wire cellLength of the wire with cell S = Potential of the cell E Potential of the cell S

The cell’s potential, E, may be calculated using the known value of the standard cell’s potential, S and the experimentally established value of the wire lengths.

Alternatively, the trial of the cell could be read directly using a high resistance voltmeter linked to the two electrodes of the two half-cells. A high resistance voltmeter enables only a little amount of current to pass and has little effect on electrolyte concentrations.

A device known as a potentiometer is used to take actual measurements. The basic premise is the same as before, but rather than a length of wire, there are two circular resistances, R1 and R2, which are directly calibrated in volts.

Internal resistance of a cell

Internal resistance is defined as the barrier to current flow supplied by the cells and batteries themselves, resulting in heat creation. Ohms are used to measure internal resistance. The relation between electromotive force (E) and internal resistance (r) in cells is represented by.

E = I (r + R)

Where e is the electromotive force (Volts), R is the load resistance, I is the current (A) and r is the cell’s internal resistance in ohms.

When we rearrange the equation above, we get:

E = IR + Ir or,

E = V + Ir

V is the potential difference (terminal) across the cell when the current (I) is flowing through the circuit in the equation above.

Conclusion

A cell’s electromotive force is always higher than the potential difference between adjacent cells. The internal resistance of a cell is thus determined by elements such as the length between the electrodes, the effective area of the electrodes, the temperature, and the solution concentration. Thus, while solving questions, if you know the formula, 

E = I (r + R), 

then you can easily solve it depending on the given values of each component.

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