Circle FormulaThe formula for circle are as stated below | ||
Description | Formula | |
Area of a Circle |
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Surface Area of a Circle | πr^2 | |
General Equation of a Circle | The general equation of a circle with coordinates of a centre(h,k), and radius r is given as:√((〖x-h)〗^2+(〖y-k)〗^2 )=r | |
Standard Equation of a Circle | The Standard equation of a circle with centre (a,b), and radius r is given as: (〖x-a)〗^2+(〖y-b)〗^2=r^2 | |
Diameter of a Circle | 2 radius | |
Circumference of a Circle | 2πr | |
Intercepts made by Circle | x^2+y^2+2gx+2fy+c=0
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Parametric Equations of a Circle | x=h+rcos θ ;y=k+rsin θ | |
Tangent |
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Pair of Tangents from a Point: | SS_1=T^2 | |
Length of a Tangent | √(S_1 ) | |
Director Circle | x^2+y^2=2a^2 | |
Chord of Contact | T=0
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Condition of orthogonality of Two Circles | 2g_1 g_2+2f_1 f_2=c_1+c_2 | |
Radical Axis | S_1-S_2=0 i.e. 2(g_1-g_2 )x+2(f_1-f_2 )y+(c_1-c_2 )=0 | |
Family of Circles | S_1+KS_2=0,S+KL=0 | |
Quadratic Equation FormulaThe formula for quadratic equation are as stated below | ||
Description | Formula | |
General form of Quadratic Equation | ax^2+bx+c=0 | |
Roots of equations | α=(-b+√(b^2-4ac))/2a β=- (-b-√(b^2-4ac))/2a | |
Sum and Product of Roots | If and are the roots of the quadratic equation ax^2+bx+c =0, then Sum of roots, α+β=-b/a Product of roots, αβ=c/a | |
Discriminant of Quadratic equation | The Discriminant of the quadratic equation is ax^2+bx+c=0 =0 given by D=b^2-4ac | |
Nature of Roots |
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Formation of Quadratic Equation with given roots | If α and are the roots of the quadratic equation, thenx-αx-β=0; x^2-(α+β)x+αβ=0
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Common Roots |
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Range of Quadratic Expression fx=ax2+bx+c in restricted domain x∈[x1,x2] |
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Roots under special cases | Consider the quadratic equation ax^2+bx+c=0
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Graph of Quadratic equation | The graph of a quadratic equation ax^2+bx+c=0 is a parabola.
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Maximum and Minimum value | Consider the quadratic expression ax^2+bx+c=0
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Quadratic Expression in Two Variables | The general form of a quadratic equation in two variables x and y is ax^2+2hxy+by^2+2gx+2fy+c To solve the expression into two linear rational factors, the condition is ∆=0 [ a h g ] ∆= [ h b f ] =0 [ g f c ] abc+2fgh-af^2-bg^2-ch^2=0And 〖 h〗^2-ab>0. This is called the Discriminant of the given expression. | |
Binomial Theorem Formulaquick formula revision for jee mains. quick formula revision for JEE mains, quick formula revision for JEE, Quick formula revision for JEE advanced. | ||
Description | Formula | |
Binomial Theorem for positive Integral Index | (x+a)^n=nC0x^n a^0+ nC1x^(n-1) a+ nC2x^(n-2) a^2+⋯+ nCrx^(n-r) a^r+⋯+ nCn.xa^n General terms = T_(r+1)=nCrx^(n-r) a^r | |
Deductions of Binomial Theorem | (1+x)^n=nC0+ nC1x+ nC2x^2+nC3x^3+⋯+nCrx^r+⋯+nCnx^n General Term=x^r=(n(n-1)(n-2)……(n-r+1))/r!.x^r
General Term=x^r=(n(n-1)(n-2)……(n-r+1))/r!.x^r | |
Middle Term in the expansion ofx+an |
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To determine a particular term in the expansion | In the expansion of(x^α±1/x^β )^n nα-r(α+β)=0 => r=nα/(α+β) | |
To find a term from the end in the expansion of x+an | T_r (E)=T_(n-r+2) (B) | |
Binomial Coefficients and their properties | In the expansion of(1+x)^n=C_0+C_1 x+C_2 x^2+⋯+C_r x^r+⋯+C_n x^n Where C_0=1,C_1=n,C_2=(n(n-1))/2! C_0+C_1+C_2+……+C_n=2^n C_0-C_1+C_2-C_3+……=0 C_0+C_2+……=C_1+C_3+……=2^(n-1) C_0^2+C_1^2+C_2^2+……+C_n^2=2n!/n!n! C_0+C_1/2+C_2/3+……+C_n/(n+1)=(2^(n+1)-1)/(n+1) C_0-C_1/2+C_2/3-C_3/4+……+((-1)^n.C_n)/(n+1)=1/(n+1)
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Greatest term in the expansion of x+an: |
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Multinomial Expansion | If n∈N then the general terms of multinomial expansion (x_1+x_2+x_3+⋯+x_k )^n is ∑_(r_1+r_2+⋯+r_k=n) n!/(r_1 !r_2 !…r_k !) x_1^r1.x_2^r2…x_k^(r_k )
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Binomial Theorem for Negative Integer Or Fractional Indices | (1+x)^n=1+nx+(n(n-1))/2! x^2+(n(n-1)(n-2))/3! x^3+⋯ +(n(n-1)(n-2)…….(n-r+1))/r! x^r+⋯,|x|<1T_(r+1)=(n(n-1)(n-2)…….(n-r+1))/r! x^r |
Also see: JEE Maths Formulas Part 2