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CBSE Class 11 » CBSE Class 11 Study Materials » Physics » Concept of Gauss Law
CBSE

Concept of Gauss Law

In this article we are going to discuss gauss law, application of gauss law , it’s equations etc. in detail and also discuss a few examples of it.

Table of Content
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According to Gauss Law, the charge enclosed divided by the permittivity equals the total electric flux out of a closed surface. The electric flux in a given area is calculated by multiplying the electric field by the area of the surface projected in a plane parallel to the field.

Gauss Law:-

The total flux associated with a closed surface equals 1/ε0 times the charge encompassed by the closed surface, according to the Gauss law.

 i.e.,∮{E.ds}=1/ε0q

A point charge q, for example, is placed within a cube with edge ‘a’. The flux through each face of the cube is now q/6ε0, according to Gauss’ law.

The electric field is the most fundamental idea in understanding electricity. In general, the electric field of a surface is computed using Coulomb’s equation, however understanding the notion of Gauss law is required to calculate the electric field distribution in a closed surface. It explains how an electric charge is enclosed in a closed surface or how an electric charge is present in a closed surface that is enclosed.

Formula of Gauss Law:-

According to the Gauss law, the total charge contained within a closed surface is proportional to the total flux contained within the surface. As a result, the total electric charge Q encompassed by the surface is; if Φ is total flux and ε0 is electric constant

 i.e.,Q = Φ ϵ0

The Gauss law formula is as follows:

Φ = Q/ϵ0

Where,

Q = total charge in the given surface,

 ϵ0 = the electric constant.

Some more clarification about this law:-

The net charge in the volume enclosed by a closed surface determines the net flow through the closed surface.

The Gauss theorem is a relationship between the ‘flow’ of electric field lines (flux) and the charges within the enclosed surface. The net electric flow stays zero if no charges are encapsulated by the surface. This signifies that the number of electric field lines entering and leaving the surface is equal.

A significant corollary of the Gauss theorem is:

The only sources (positive charges) and sinks (negative charges) of electric fields confined by the surface account for the electric flux from any closed surface. The electric flow is unaffected by any charges that exist outside the surface. Furthermore, only electric charges can serve as electric field sources or sinks. For example, magnetic fields that change cannot operate as electric field sources or sinks.

Because it encloses a net charge, the net flow for the surface on the left is non-zero. Because the right-hand surface does not encapsulate any charge, the net flux is zero.

Application of Gauss Law:-

  1. In the case of a charged ring of radius R rotating on its axis at a distance x from its center.                              X = 0 and E = 0 are at the center.

  1. At a distance of ‘r’ from an infinite charge line 

Where  λ is the linear charge density.

  1. E =20K ,where σ is the surface charge density, is the intensity of the electric field near a plane sheet of charge.

  2. In a medium with a dielectric constant of K, the intensity of the electric field near a plane charged conductor E = σ/Kε0. When air is used as the dielectric medium, Eair = σ/ε0.

  3. Where σ is the surface charge density, E = σ/ε0 is the field between two parallel plates of a condenser.

Conclusion:-

Gauss’s law, often known as Gauss’s flux theorem (or just Gauss’s theorem) in electromagnetic theory, is a law that relates the distribution of electric charge to the resulting electric field. It asserts that the flux of the electric field out of any closed surface is proportional to the electric charge enclosed by the surface, regardless of how that charge is distributed, in its integral form.

 
faq

Frequently asked questions

Get answers to the most common queries related to the CBSE 11th Examination Preparation.

What is the relationship between Gauss and Coulomb’s laws?

Ans : Gauss law may be used to deduce Coulomb’s law and vice versa, which is one of the essential...Read full

How do we choose the right Gaussian Surface for each situation?

Ans : In order to select an acceptable Gaussian Surface, we must consider the fact that the charge-...Read full

How do you use Gauss’ law to calculate the electric field?

Ans : Normally, the Gauss law is employed to calculate the electric field of symmetric charge distr...Read full

What is the Gauss theorem’s differential form?

Ans : The electric field is related to the charge distribution at a specific place in space by the ...Read full

What is the relationship between electric flux and Gauss law?

Ans : When it comes to the relationship between electric flux and Gauss law, the law indicates that...Read full

Ans : Gauss law may be used to deduce Coulomb’s law and vice versa, which is one of the essential relationships between the two laws. We can also state that Coulomb’s law is equivalent to Gauss’s law, implying that they are almost identical. While electrodynamics has a lot to say about this relationship.

Ans : In order to select an acceptable Gaussian Surface, we must consider the fact that the charge-to-dielectric constant ratio is given by a (two-dimensional) surface integral over the charge distribution’s electric field symmetry. We’ll need to know about three potential scenarios.

  • When the charge distribution is spherically symmetric, it is called spherical.
  • When the charge distribution is cylindrically symmetric, it is called cylindrical.
  • When the charge distribution has translational symmetry along a plane, it is called a pillbox.
  • Depending on where we want to calculate the field, we can pick the size of the surface. When there is symmetry, the Gauss theorem is useful for locating the field since it informs us how to find it.

Ans : Normally, the Gauss law is employed to calculate the electric field of symmetric charge distributions. When using this law to solve the problem of the electric field, there are multiple processes involved. The following are the details:

  • First, we must determine the charge distribution’s spatial symmetry.
  • The next step is to select a proper Gaussian surface that has the same symmetry as the charge distribution. Its ramifications must also be determined.
  • Calculate the flux across the surface by evaluating the integral sE over the Gaussian surface.
  • Calculate the amount of charge contained within the Gaussian surface.
  • Calculate the charge distribution’s electric field.

Ans : The electric field is related to the charge distribution at a specific place in space by the differential form of Gauss law. To clarify, according to the law, the electric field’s divergence is equal to the volume charge density (ρ) at a given position. It’s written like this:

 ΔE = ρ/ε0

Here, ε0  = permittivity of free space.

Ans : When it comes to the relationship between electric flux and Gauss law, the law indicates that if the volume defined by the surface includes a net charge, the net electric flux in the closed surface will be zero.

We’ll start by looking at the Gauss law to see how the two are related.

The Gauss’s law can be written as follows:

                                 ΦE = Q/ε0

Here,

E = electric flux through any volume V enclosed by a closed surface S.

Q is the entire charge contained within V, and o is the electric constant.

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