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Different Cases in Third Order Reaction

The third-order reaction can be described as the process in which only one out of three reactants reacts at any given time.

The third-order reaction can be described as the process in which only one out of three reactants reacts at any given time. This reaction can also be described as the slowest of all the reactions where the rate constant can reach up to 0.056 Lmol-1s-1 at 25 °C. This type of reaction has many different cases where they all have different rate constants, and they also have different ways to categorize them, as shown below (Garrett, 2006).

To determine the rate constant of a reaction, you need to look at the number of collisions between reactants and products per second. This collision occurs during the transition state because it has the highest energy of all the molecular states. Third-order reactions always have an order greater than one because there are more than two reactants in these types of reactions.

How To Solve For Nth Order Rate Constants

Solving for nth-order rate constants is fairly simple, assuming you have a good understanding of how they work. For example, if you’re given a reaction you can rearrange to find (1/2)[A][B] and then substitute in your initial concentration of A and B to solve for [C]. 

In many cases, however, it can be far more complicated to solve for rate constants because they don’t necessarily behave linearly in every situation. To make things more difficult, other factors—like stoichiometry or temperature changes—can complicate things further still.

Third-order reaction kinetics

A third-order reaction means that three molecules of reactant are required to form one molecule of product. The rate equation is as follows: Rate = k[A][B]x[C]y where x and y represent stoichiometric coefficients and k is a rate constant (also known as a reaction order). 

Many reactions do not follow first or second-order kinetics. In third-order reactions, we can determine whether it follows zero, first, or second-order kinetics using a simple analysis technique.

Averaging different cases of third-order reactions

To solve third-order reaction problems, you need to calculate a single value called a rate constant. This is known as an average rate constant and it can be used to work out how fast a chemical reaction will progress for any given concentration of reactants. The faster reactions will have higher values, but these calculations only take into account instantaneous rates. 

A high value could mean that reactions happen too quickly over time or not quickly enough depending on other factors that play into chemical reactions. There are four different cases in which you can find a third-order reaction: zero-order, first-order, second-order, and third-order reactions.

How do you find the rate constant for a third-order reaction?

To find the rate constant for a third-order reaction, you’ll need to use the following formula: k = [A]^3[B]^-1[C]^2/([D][A]+[C]) The symbols used in the formula are explained as follows: [A] is the concentration of species A, [B] is the concentration of species B, and so on. The square brackets ([ ]) indicate concentration. This can make things a little confusing when trying to find rate constants for a third-order reaction, as you must know the concentrations of all three reactants—and that doesn’t always happen. Luckily there’s an alternative way to solve for k: 1) Write down the half-reaction with only your reactant inside parentheses.

Conclusion

A third-order reaction means that the rate of the overall reaction depends on three consecutive steps. In our case, we are talking about the rate being dependent on how fast the two reactants A and B react with each other to produce products C and D and then with each other to form products E and F, respectively.

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Why can't a reaction be more than 3?

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