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JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Chemistry » BrF5 Molecular Geometry and Bond Angles

BrF5 Molecular Geometry and Bond Angles

The BrF5 or the Bromine pentafluoride is an interhalogen chemical compound used for various analytical purposes. In this article, we will learn about BrF5 molecular geometry.

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The BrF5 or the Bromine Pentafluoride is a compound well-known for its high toxicity and corrosive nature. The other properties of this compound include strong odour and colourlessness. Its method of preparation includes treating bromine with fluorine in a large amount at a temperature of more than 150°C. There is another set of properties as well, including usage, electronic configuration of the compound, molecular geometry, and bond angles. The BrF5 molecular geometry is a square pyramidal shape, and the bond angles are 90° each.

BrF5 or Bromine Pentafluoride

BrF5 is an interhalogen compound, meaning that the molecules of this compound contain two or more different halogen atoms but no atoms of the elements belonging to any other group. The electronic configuration for this compound can be presented as sp³d². As for the uses of this toxic and corrosive compound, it is mostly used in rocket propellants and also for the processing of uranium.

The valence electrons present in this compound are a total of 42 in number. Besides rocket propellants and uranium processors, it is also used for various analytical and laboratory purposes.

Molecular Geometry

The structure of atoms in the three-dimensional arrangement that constitute the molecules is defined as molecular geometry. Different chemical compounds have their molecular geometry. Here, we will focus on the molecular geometry of one specific compound, Bromine Pentafluoride. It can influence some of the properties of the compound like colour, magnetism, the biological activity of the compound, reactivity, phase of matter and polarity. As for the molecular geometry of BrF5, it is of square pyramidal shape.

What is Square Pyramidal Molecular Geometry?

As we have already discussed, the molecular geometry of BrF5 is square pyramidal. The square pyramidal shape can be defined as a molecular shape that forms when there are five bonds and one lone pair in the molecule. When we observe the shape, it describes the shapes of the compounds with the ML5 formula where L is a ligand, i.e., an ion or atom which binds the other atoms of the compound to the central atom. The square pyramidal molecular geometry is a common shape for certain compounds of the main groups, which consist of active lone pairs.

Bond Angle

The bond angle for any compound can be defined as the angle between the orbitals of the bonding pair of electrons with one central atom in a specific compound, molecule, or complex. It also helps us identify the geometrical shape and the nature of the compound. For example, the bond angle for carbon dioxide (CO2) is 180°; from this information, we can conclude that the geometrical shape of CO2 is linear.

Another example of H2O can be taken for reference. An atom of oxygen has 6 electrons, of which 2 of them bond with the hydrogen atom, leaving two lone pairs of electrons behind. Hence, by this bonding, one molecule of H2O has a bond angle of 104.5° between them.

Bond Angle for the Compound BrF5

The BrF5 or the bromine pentafluoride has a bond angle of 90°. Therefore, the angle formed between the central atoms and the other ones has an angle of 90° between them. As for the total number of 90° bond angles in the bromine pentafluoride, the compound consists of 5 bond pairs of atoms and one lone pair. Also, it has to be kept in mind that there are no perfect bond angles for 90°.

How to Calculate the Bond Angle of a Compound?

The measurement of the bond angle depends upon the number of lone pairs of electrons present between them. The most common method to find the bond angle of any compound traces its way to the VSEPR theory. The VSEPR theory is used to find out the geometry of the compound, hence helping us know the bond angle measurements that a compound has within it. The theory states that each atom in a molecule attains a geometrical shape that minimises the force of repulsion between electrons in a valence shell of that particular atom. For example, ammonia has one lone pair of electrons, and its geometrical shape is trigonal pyramidal; hence it has a bond angle of 107.5°.

Conclusion

It is important to know the characteristics of the bond angle and the molecular geometry of a compound, such as the reactivity, nature, reaction properties, and precautions while handling them since we have already seen that BrF5 is highly corrosive and can cause severe injuries to our skin if not handled carefully. The bond angle of BrF5 was calculated to be 90°, and with this information, we were also able to find out its molecular geometrical shape. This can be done with the other compounds or molecules also if we can find out their nature, electronic configuration, and valence shell electrons.

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Frequently asked questions

Get answers to the most common queries related to the JEE Preparation.

How many atoms are there in the BrF5 plane?

Answer: The BrF5 compou...Read full

What is the oxidation state of bromine (Br) in BrF5?

Answer: The oxidation number of bromine in BrF5...Read full

Are the lengths of all the bond angles equal in BrF5?

Answer: No. Since the lone pair of electrons is only one and the number of bond pair electrons is 5...Read full

What is the point group for BrF5?

Answer: The compound BrF5...Read full

Answer: The BrF5 compound has four fluorine atoms on the base of the compound. The central atom is bromine which forms five sigma bonds with the other fluorine atoms in the compound.

 

Answer: The oxidation number of bromine in BrF5 is counted as +5. It means that bromine will lose 5 electrons while participating in any chemical reaction being a part of this compound.

Answer: No. Since the lone pair of electrons is only one and the number of bond pair electrons is 5, none of the angles is accurately 90° in measurement. Hence, the length of all the bond angles in BrF5 is not equal.

Answer: The compound BrF5 belongs to the point group of C4v.

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