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# Voltage Drop Formula With Solved Examples

Explore more about the Voltage drop formula with solved examples.

## Voltage Drop Formula

Voltage drop describes how the energy supplied by a voltage source is diminished as electric current runs through electrical circuit elements that do not supply voltage (passive elements).

The quantity of electric power produced or consumed is measured when an electric current runs across the voltage drop. A voltage drop is a decrease in electric potential that occurs as a current flows across an electrical circuit. It’s also a strategy that works in the same way as an electric circuit.

Furthermore, each point in the circuit can be assigned a voltage proportional to its “electrical elevation.” To put it another way, the voltage drop is the difference in arithmetic between a higher and lower voltage.

Furthermore, the voltage drop between a component’s terminals multiplied by the current flowing through it equals the amount of energy per second (power) delivered to that component in a circuit.

Voltage drop describes how the energy supplied by a voltage source is diminished as electric current runs through electrical circuit elements that do not supply voltage (passive elements). Because the supply energy is wasted, the voltage drop across conductors, connectors, and internal resistances of the source are undesirable. Because the provided power performs efficient work, the voltage drop across active circuit elements and loads is desirable.

The formula for voltage drop is as follows:

V = IZ

Here, I = current

Z is the impedance in ohms(Ω).

Solved Examples

1. A circuit with a resistance of 10Ω has a current of 9A flowing through it. Calculate the voltage loss in the circuit.

Here,

Current (I)  = 9 A

Impedance (Z) = 10 Ω

According to the voltage drop formula,

V= IZ

V = 9 × 10

V = 90 volts

1. A 15Ω and a 30Ω lamp are connected in series. It is given a 4 A current to pass through it. Determine how much voltage has dropped.

Impedance( Z ) = (15 + 30) Ω

Z = 45 Ω,

Current ( I )= 4A

According to the voltage drop formula,

V = IZ

V = 4 × 45

V= 180 V

1. When a current flow is 17A and a resistance of 26 ohms, how do you calculate voltage drop using the voltage drop formula?

It is given that,

Current (I) = 17A

Impedance (Z )= 26 Ω

Now by, the voltage drop calculation formula we get,

V = I × Z

V = 17 × 26

V = 442 V