Latent Heat Formula with Solved Examples

Latent Heat Formula

• The heat required to transform a substance to a fluid or gaseous state, or fluid to a gaseous form, is latent heat.
• Condensed water heat, vaporisation heat, and so forth are several of the ones given to it based on the various phases.
• Latent heat is the energy used or released by a substance throughout a phase shift. It might be a transition from a gaseous phase or a substantial change and back.
• Latent heat is connected to the heat characteristic enthalpy. 

The latent heat Formula is as follows:

L = Q/M

where,

L = a substance’s specific latent heat

Q = quantity of heat

M = the substance’s mass

The equation for Latent Heat of Vaporization

• Latent heat of vaporisation seems to be the heat absorbed or emitted as matter fades away, switching phase from liquid to fixed amount of gas temp.
• The most well-known source of heat is liquid vaporisation. The quantity of heat necessary to turn 1 g of something like a liquid into a vapour without affecting the fluid’s temperature is the heat of vaporisation.

Solved Examples

1. Calculate the estimated latent heat of a 5 kg substance if the amount of heat required for a phase shift is 300 kcal.

The parameters are as follows:

Q = 300 kcal

M = 5 kg

The latent heat formula is as follows:

L = Q / M

L = 300 / 5

L = 60 kcal/kg

As a result, the latent heat value is 60 kcal/kg.

1. A chunk of metal seems to weigh 60g around 20°C. 0.5g of the vapour condenses before being submerged in a steam stream at 100°C. Compute the particular heat of the metal, assuming the latent heat for steam = 540 cal/g.

Let c become the metal’s specific heat. The metal has gathered heat.

Q = mcΔt

Q = 60 x c x (100 – 20)

Q = 60 x c x 80 cal

The steam’s heat is expelled.d

Q = m × L

Q = 0.5 × 540 cal

According to the concept of mixing, the amount of heat provided is equal to the amount of heat absorbed.

0.5 × 540 = 60 × c ×80

c = 0.056 cal/g ⁰C

As a result, the specific heat value at 0C is 0.056 cal/g.