Distance Speed Time Formula

Distance Speed Time Formula

Small Description: Meta-description: In physics, the three most essential variables are speed, distance, and time. These three variables also surely contribute in the solving of a range of physics problems.

In physics, the three most essential variables are speed, distance, and time. These three variables also surely contribute in the solving of a range of physics problems. Before you can grasp the formula, you must first learn the meanings of the words. Let’s have a look at how distances, speed, and time are defined.

Distance

Distance is the sufficient space that lies between any two places. It may also be described as a measure of how much something moves. Distance is also expressed in terms of miles, kilometres, metres, centimetres, millimetres, yards, and inches.

Speed

The pace at which an item goes from one point to another is referred to as speed. The speed of an item is defined as the magnitude of its velocity. It is, without a doubt, a scalar quantity.

Time

The passage of time is alluded to as the progression of events. This transition is planned in such a manner that it advances from a historical perspective to a future one. In a nutshell, if there is a system in nature that is always altering, it is timeless. Furthermore, time is an intangible entity that isn’t felt, or tasted. It is only possible to gauge its passing. Time is considered as the fourth dimension of existence, according to scientists. Physicists utilize time to explain occurrences in three-dimensional space.

Formulas 

Distance = speed × time

OR

OR

• S.I unit for distance = metre; abbreviated as m
• S.I unit for speed = metre/second; abbreviated as m/s
• S.I unit for time = second; abbreviated as s

Solved Examples

1. In two hours, an automobile travelled 90 kilometres. What is the speed of it?

Here, the distance is given as 90km and the automobile takes 2 hours to cover it so using the basic formula speed = distance/time we can get the speed.

Speed = 90/2 = 45 km/hr

2. Calculate the time it takes a bicycle to traverse 4 kilometres at the rate of 10 kilometres per hour.

distance = 4km 

Speed = 10km/hr

3. What would be the new speed if the distance was double and the time was cut to half?

Assume the speed was “s” earlier, the time “t” earlier, and the distance “d” earlier.

s = d/t —-(1)

2d = new distance

t/2 = new time

s’ = 2d/(t/2) = new speed

4d/t = s’

4s = s’

The new magnitude of speed will be 4 times that of the previous one.