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Velocity of object, image along perpendicular direction of priciple axis
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Problem Velocity of object, image along perpendicular direction of priciple axis

Deependra Singh Naruka
#BTech (Mechanical) # Senior Faculty of Physics #Kota (Rajasthan) #Ex Bansal classes faculty #Ex Narayana IIT academy Faculty # I am teachin

U
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  1. Problems linked with mirror and mechanics problem Coefficient of restitution SHM


  2. Q. If the object is moving upward (perpendicular to principle axis ) with 2m/s. Find velocity of image formed by concave mirror of focal length 20cm and object is placed 30cm in front of concave mirror 2 Magnification (m) UA LA e dt o0m V+ -60 ) x2 By using mirror formula V2 -60m


  3. Q. Object is placed 30cm in front of concave mirror of focal length 20cm. Velocity of object is 5m/s at an angle 37. Find speed of image formed 3im 21 V -60m dt Component of Velocity of image along x-axis


  4. here, (Height of Image), hi =0 & (Height of object), ho = 0 Component of velocity of image perpendicular to principle axis will be calculated by differentiating dli IS df dlt Component of velocity of image along y-axis


  5. Q. If point object is placed 2cm above principle axis and is moving parallel to principle axis with 2cm/s then find speed of image hiuz- Now for velocity along y-axis Here only Height of object is constant so rate of change of Height of object with respect to time is zero olt V Mn- V' Along x-axis


  6. Q. Find length of image formed of object AB LONGITUDINAL MAGNIFICATION For longitudinal magnification, there may be two cases 1. If length of object is comparable to object distance then in this case consider two end points of object and calculate there image distance of both the objects 2. If length of object is very less compared to object distance 0


  7. Q. Find length of image formed 2mm Length of image Longitudinal magnification duu for small objects Length of object