The Circle x2 + y2 = 5 Meets the Parabola y2 = 4x at P and Q Then the Length of PQ is Equal to

Answer:

• Solving x² +y² = 5 and y² = 4x simultaneously we get the value of x = 1 and -5 but we cannot take positive value so x = 1. 
• Now y = 2, -2.
• P = (1,2) and Q = (1,-2)
• By distance formula we have PQ = 4.