Sin b plus a plus cos b minus a sin b minus a cos b plus a?

Answer:  Simplify the given expression.
[sin⁡(B+A)+cos⁡(B-A)] / [sin⁡(B-A)+cos⁡(B+A)]

=[sin⁡Bcos⁡A+cos⁡Bsin⁡A+cos⁡Bcos⁡A+sin⁡Bsin⁡A]  /  [sin⁡Bcos⁡A-cos⁡Bsin⁡A+cos⁡Bcos⁡A-sin⁡Bsin⁡A]

=[cos⁡A(sin⁡B+cos⁡B)+sin⁡A(cos⁡B+sin⁡B)]  /  [cos⁡A(sin⁡B+cos⁡B)-sin⁡A(cos⁡B+sin⁡B)]

=[(sin⁡B+cos⁡B)(cos⁡A+sin⁡A)] / [(sin⁡B+cos⁡B)(cos⁡A-sin⁡A)]

=(cos⁡A+sin⁡A) / (cos⁡A-sin⁡A)