The bond order of B2 molecule is_______.

Answer: The bond order of B2 molecule is 1.

Bond order

The bond order shows the number of chemical bonds present between a pair of atoms. Half of the difference between the number of electrons in bonding orbitals and antibonding orbitals is called the Bond Order Formula.

Bond order =1/2[N_b–N_a]

Where,

N_b= Number of bonding electrons

N_a= Number of antibonding electrons

Bond order of B₂ molecule

The atomic number of Boron (B) is 5, the electronic configuration of Boron is,

B(Z=5)=1s²2s²2p¹ 

Bond order =1/2[N_b-N_a]

Bond order =1