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JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Physics » What is the Differential Form of Gauss’s Theorem

What is the Differential Form of Gauss’s Theorem

Gauss theorem states that total electric flux out of a closed surface equals the charge enclosed divided by the permittivity. Read about the differential form of Gauss’s theorem.

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Gauss law is one of the fundamentals of physics. It is regarding the production of electric fields by the distribution of charges over the region.

Gauss’s law states that the flux coming out of the surface equals 1 /ϵ0 of the charge enclosed by the surface. Gauss theorem has various applications. 

In this study material notes, we learn about the differential form of Gauss’s theorem. 

Conditions for Gauss’s law

  • The symmetricity over charge distribution is required.
  • The electric field must be symmetric, equal, and constant at all points of the Gaussian surface.
  • The θ angle between vector A and vector E must be the same at all points of the surface.
  • The Gaussian surface must not pass through any point charge (charge must be enclosed in the Gaussian surface).

Gauss’s law equation

Integral equation of Gauss’s law:

∫E⋅dA = Q/ε0

Where,

E is the electric field vector

Q is the enclosed electric charge

ε0 is the electric permittivity of free space

A is the outward pointing normal area vector

Electric flux

Flux is a measure of the strength of a field passing through a surface. Electric flux is expressed as:

Φ = ∫E⋅dA

Flux is a scalar quantity.

Electric flux is defined as the measure of the number of electric field lines crossing an area.

The SI unit of electric flux is Nm2/C.

ΦE = E⋅S = EScosθ

Another statement of Gauss’s law states that the net flux of an electric field of a given surface divided enclosed charge should be equal to a constant.

Differential form of Gauss’s law

According to Gauss’s theorem, electric flux in a closed surface is equal to 1/ϵ0 times of charge enclosed in the surface.

Gauss law is represented by-. 

Where ‘q’ represents the total charge of the surface, and ‘∈0’ represents the permittivity of free space.

Gauss theorem has different applications.

The equation gives the electric field intensity of an infinitely long charged wire

E = λ/2π∈0r

where,

E = Electric field

λ = Linear charge density 

∈0 = Permittivity of free space 

Where λ = q/l (where λ denotes Linear charge density, q denotes the total charge of the selected piece, and L denotes the total length of the selected piece).

The equation gives the electric field intensity due to an infinite plane sheet of charge:

E = σ/2∈0

Where,

 E = Electric Field 

σ = Surface charge density 

∈0  = Permitivity in free space.

Where, σ = q/A (where, σ denotes surface charge density, q denotes total charge of sheet, A denotes area of sheet).

According to the differential form of Gauss’s law, the divergence of the electric field at any point in space is equal to 1/∈0 times the volume charge density ‘ρ’ at that point.

Gauss divergence theorem is represented by

ttt

Application of Gauss’s Law

  • Here, λ linear charge density in case of an infinite line of charge, at a distance ‘d’. E = (1/4πdε0) (2π/d) = λ/2πdε0.
  • Here, σ is the surface charge density, and then the intensity of the electric field near a plane sheet of charge is represented by E = σ/2ε0K.
  • Here, the dielectric constant is K, and the medium is an AIR, then the electric field in the air = σ/Kε0. The intensity of the electric field near a plane charge conductor E = σ/Kε0 (in the medium of dielectric constant).
  •  E = σ/ε0 is applied when the field is between two parallel plates of a condenser, where σ is the surface charge density.

Conclusion

Gauss law derives the relationship between the charge enclosed and the electric flux. Like Newton’s law, it is also a universal law. But it is useful under certain conditions that it is applicable to closed surfaces, the standard shape of Gaussian surfaces (spherical, cylindrical, or plane symmetry). The change distribution should be symmetric. It is not applicable for open surfaces. Gauss law is also applied to non-uniform surfaces.

faq

Frequently asked questions

Get answers to the most common queries related to the IIT JEE Examination Preparation.

What does Gauss’s law state?

Ans. Carl Friedrich Gauss states that the flux coming out of the surface equals 1 /ϵ...Read full

What are the limitations of Gauss’s law?

Ans. Gauss’s law is just limited to an electric field; it does not tell us about the magnetic fie...Read full

What is electric flux? What is its formula?

Ans. The number of electric field lines crossing an area is known as electric flux. The SI unit of...Read full

How do we choose an appropriate Gaussian surface for different cases?

Ans. To choose an appropriate Gaussian surface, we have to consider the state that the ratio of ch...Read full

Ans. Carl Friedrich Gauss states that the flux coming out of the surface equals 1 /ϵ0 of the charge enclosed by the surface. The electric field must be symmetric, equal, and constant at all points of the Gaussian surface.

Ans. Gauss’s law is just limited to an electric field; it does not tell us about the magnetic field, currents, waves, etc. It is also applied only on closed surfaces of any shape. The charge distribution should be symmetric.

Ans. The number of electric field lines crossing an area is known as electric flux. The SI unit of flux is Newton metre square per Coulomb or Nm2/C.

The CGS unit of electric flux is done.

Ans. To choose an appropriate Gaussian surface, we have to consider the state that the ratio of charge and the dielectric constant is given by a (two-dimensional) surface integral over the electric field symmetry of the charge distribution. There are three different cases:

In spherical shape, when the charge distribution is spherically symmetric.

In cylindrical shape, when the charge distribution is cylindrically symmetric.

In pillbox shape, when the charge distribution has translational symmetry along a plane.

We choose the size of the surface depending on where we want to calculate the electric field. Gauss’s theorem helps find the electric field in certain symmetries.

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