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Parallel Plate Capacitor

Let’s discuss the capacitance of a parallel plate capacitors, the amount of charge passed across the plates, the potential changes.

The parallel plate capacitor helps to understand the potential that changes according to the charge passed. The parallel plate capacitor calculation is simple and resolvable. Before understanding the deep functionalities, we should know the parallel plate capacitor’s meaning and its importance in detail. Then we can arrive to determine the formula of a parallel plate capacitor.

What is a Parallel Plate Capacitor?

Parallel plate capacitors have electrodes and insulating material to form sequences. It can store a finite, limited amount of energy. If a battery is connected across two parallel plates, the plates are charged and form an electric field. This process is called a parallel plate capacitor.

If more charge is supplied between the parallel plates, then the potential will be increased, and it will provide charge leakage straight away. And if we place another plate next to the positively charged plate, then the negative charge flows in the direction of the positively charged plate.

Since both the plates have charges, plate 2’s negative charge reduces the potential difference on plate 1, whereas plate 2’s positive charge increases the potential difference on plate 1. More charge will be provided to plate 1 because of the negative charge impact on plate 2. So, the potential difference is less on plate 2. 

Parallel Plate Capacitor Formula

The direction of the positive test charge is called the direction of the electric field. The change in electric charge concerning the electric potential is called capacitance. And the capacitance acts as a body to store all the electric charges. 

Consider the parallel plate capacitor consists of two plates and the area is A, the distance between the plates is “d”.

The formula to determine the parallel plate capacitor is 

C=kϵ0A/d

ϵo is the permittivity of space, i.e. (8.854 × 10−12 F/m)

k is the relative permittivity 

Parallel Plate Capacitor Derivation

The figure below depicts a parallel plate capacitor. It has two large plates placed parallel to each other at a distance “d”. 

The plates’ distance is smaller than the area of the conductive plate. So, it is called infinite plane sheets. The charge density can be determined using the below formula

For plate 1:

a1

Let us separate the regions of the parallel plate capacitor for calculation purposes,

Area 1 – the left area to the plate 1

Area 2 – the area between the plate 1 and 2

Area 3 – The right area of plate 2

Calculation of electric field around parallel plate capacitor:

For Area 1, The magnitude will be the same because of the infinite plane sheets. Since the plane sheets’ direction is placed opposite each other, the electric field will become 0.

a2

For Area 2, The magnitude and the electric field’s direction are the same. So, the equation will be

a3

For Area 3, the magnitude is the same as that of area 1. So the electric field is generated because of the plane sheets present in that region.

a4

If the direction of the electric field is from positive to negative plate and if it is uniform in nature, then the potential difference is calculated by using the distance created between the two plates with respect to the electric field generated.

a5
a6

Let’s see some examples for better understanding

Example 1

A parallel plate capacitor kept in the air has an area of 0.50m2 and the distance between the plates 0.04m. Estimate the parallel plate capacitor.

Solution:

Given:

Area A = 0.50 m2,

Distance d = 0.04 m,

relative permittivity k = 1,

ϵo = 8.854 × 10−12 F/m

The parallel plate capacitor formula:

C=kϵ0A/d

= 8.854×10−12 × 0.50 / 0.04

= 4.427 x 10−12 / 0.04

So, C = 110.67 x 10−12 F

Example 2

Calculate parallel plate capacitor’s area in the air by considering the capacitance as 25 nF and distance between the plates is 0.04m.

Solution:

Given:

Capacitance = 25 nF,

Distance d = 0.04 m,

Relative permittivity k = 1,

ϵo = 8.854 × 10−12 F/m

The parallel plate capacitor formula 

C=kϵ0Ad

A=dCkϵ0

= 0.04 × 25×10−9 / 1×8.854×10−12

A = 1 x10−9 / 8.854 ×10−12

So, the area of the parallel plate capacitor is 112.94 m2.

Conclusion

The parallel plate capacitance depends on the distance between the plates and the area. The single capacitor cannot store the high electric charge, so two parallel plates are needed to store a high amount of electric charge. The parallel plate capacitors are mostly used in DC power supplies, automobile industries etc. Each application has various advantages and characteristics related to capacitance. Calculation of capacitance is nothing but measuring the capacitor’s capability to store energy in the form of charge. The parallel plate capacitor is mainly used to store a large volume of electric charge. The single capacitor can hold only a few amounts of electric charges.

In contrast, the two parallelly placed plates create an electric field when connected to the battery and store a huge amount of electric charge. The calculation and importance of parallel capacitance have been explained in detail. Mostly parallel plate capacitor jee notes are famous among the students who prepared for jee examinations. 

faq

Frequently asked questions

Get answers to the most common queries related to the IIT JEE Examination Preparation.

What amount of energy can be stored by a parallel plate capacitor?

Ans. A parallel plate capacitor can store a finite amount of energy.

What is established between the two parallel plates if connected by a battery?

Ans. The two parallel plates are charged electric fields when the battery is connected. ...Read full

What is capacitance?

Ans.The capability to store the electric charge is known as capacitance.

What is a dielectric medium?

Ans. The distance between the plates is filled with a dielectric medium.

What kind of charges are carried by the two plates of the capacitor?

Ans. The two plates of the capacitor carry both equal and opposite charges.