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JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Physics » Gauss’s law and its applications to find field

Gauss’s law and its applications to find field

In this article, we will discuss the concept of Gauss law, Gauss law application, applications of Gauss law, limitations of Gauss Law and more. Gauss law is used to find the electric field. It gives a relation between electric charge and electric flux.

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According to Gauss Law, total electric flux outside a closed surface is equal to the charge enclosed which is separated by the permittivity. The electric flux is the product of electric field and area of the surface which is projected in a plane and normal to the field.

Electric Field

The electric field is defined in mathematical terms as a vector field which can be connected with each point in space. At that point the force per unit charge is exerted on a positive test charge which is at rest.

The electric field is given as

Here, 

E = electric field

F = force

q = charge

Unit:

Gaussian Surface

A closed surface in a 3D Space whose flux of a vector field is determined which may be the magnetic field or electric field or gravitational field is called the Gaussian surface.

Gauss Law

According to the Gauss Law total electric flux outside the closed surface is equal to the charge enclosed by that surface divided by the permittivity (). The electric flux in an area is the product of electric field and the area of the surface perpendicular to the field.

Total flux associated with the surface is 1/ ε0 times the total charge enclosed by the closed surface.

Hence, it is given as

Electric Field using Gauss Law

The electrostatic field/electric field can be determined by following these steps.

  1. Firstly, we need to find the spatial symmetry (spherical, planar, cylindrical) of distributed charge.
  2. Then, we have to determine a gaussian symmetry which is similar to the symmetry of spatial arrangement.
  3. Determine integral along with the gaussian surface and then define flux.
  4. Determine the charge which is enclosed by the Gaussian surface.
  5. Determine the electric field of distributed charge.

Gauss law in a Conductor

Electric field inside a conductor is always zero. As the net or total electric charge in the conductor becomes zero. Therefore, no electric flux is trapped or enclosed in the conductor. 

Hence Gauss’s law within a conductor given as

Gauss Law Application

There are many applications of Gauss law.

  1. Electric field when a charged ring having radius R on its axis at a distance of x from the centre is given as

2. Electric field between two plates which are parallel to each other is given as

Here, = charge density

Electric field Due to Infinitely Long Straight Uniformly Charged wire 

Electric field due to Infinitely long uniform charge will be determined easily by applying Gauss law. It is a Gauss law application. Let us consider a line charge in the form of a thin charged rod having linear charge density λ.

For determining the electric intensity at a point P at a normal distance r from the rod, we need to consider a right circular closed cylinder having radius equals to r and length is l with an infinitely long line of charge as its axis.

The magnitude of the electric field intensity at all points on the curved surface of the Gaussian surface (cylinder) is the equivalent because the distance of all points are the same from line charge.

Hence,

Curved surface area =2Πrl

Now, we know 

And 

And also, Gaussian surface is given as

Therefore, by combining these three equations we get

Here,

=Line Charge Density

l = length

Hence, Electric field due to Infinitely long uniform charge is

Limitations of Gauss Law

There are some limitations of Gauss law which are given here.

  1. One cannot determine the electric field for any conductor. Gauss’ law is only useful for some symmetrically charged conductors such as spheres, cylinders, straight wires, flat sheets, etc. to calculate electric fields.
  2. Gauss law is applicable when the conductors have charges inside them.
  3. You can use Gauss’ law to determine an electric field due to a point charge. But Gauss law is not used to determine an electric field for an electric dipole and other conductors having irregular shape. Coulomb’s law is used to find the electric field of an electric dipole.

Conclusion

The electric field is defined in mathematical terms as a vector field which can be connected with each point in space.

The electric field is given as

A closed surface in a 3D Space whose flux of a vector field is determined which may be the magnetic field or electric field or gravitational field is called the Gaussian surface.

represents the Gaussian surface of a cylinder.

Electric field when a charged ring having radius R on it’s axis at a distance of x from the centre is given as

Electric field between two plates which are parallel to each other is given as

Here, = charge density

According to the Gauss Law total electric flux outside the closed surface is equal to the charge enclosed by that surface divided by the permittivity ().

Gauss law is given as

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