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JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Physics » EMF of two given primary cells

EMF of two given primary cells

In this article we will learn about EMF and the detailed procedure of comparing the emf of two primary cells.

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It is generally agreed that the total distance between an atom’s nucleus and the outermost orbital of an electron is referred to as the atomic radius. In simpler terms, it can be defined as something akin to the radius of a circle, where the nucleus is located in the centre of the circle and the outer border of the circle represents the electron’s outermost orbital. As you begin to move across or down the periodic table, you will see trends that will help you understand how atomic radii vary.

When an atom has an effective nuclear charge (Z), it means that the valence electron is feeling a net positive charge on its surface. A small amount of positive charge is shielded by the core electrons, thus the valence electron is not affected by the total amount of positive charge. You can get a more in-depth explanation of shielding and effective nuclear charge here. The atomic size of an atom is substantially influenced by the Z factor. As a result, as the value of Z drops, the atomic radius increases as a result of increased screening of electrons away from the nucleus, which reduces the attraction between the nucleus and electron. Given that Z lowers as one moves down a group and from right to left across the periodic table, it follows that the atomic radius will rise as one moves down a group and from right to left across the table.

Atomic radii: An overview

Atomic radii are the diameters of solitary, electrically-neutral atoms that are unaffected by the bonding topologies that hold them together. Because electrons are filling outer electron shells as one progresses downwards in the Periodic Table of the Elements, the average atomic size increases as one moves down the Periodic Table. On the other hand, as one proceeds over the Periodic Table from left to right, the atomic radius of the atoms decreases. Despite the fact that more electrons are being added to atoms, they are all located at approximately the same distance from the nucleus; thus, the increasing nuclear charge “pulls” the electron clouds inwards, resulting in decreased atomic radii.

Covalent Radii: The covalent radius is a measure of the size of an atom that is a component of a single covalent bond in an element. Picometres (pm) or angstroms (Å) are the most often used units of measurement, with one angstrom equalling 100 picometres.

Van-der Waals Radii: The Van der Waals radius, abbreviated as rw, of an atom is the radius of an imaginary hard sphere that represents the distance between two atoms that are closest to one another. It was given this name in honour of Johannes Diderik van der Waals, winner of the 1910 Nobel Prize in Physics, because he was the first to recognise that atoms were more than just points and to demonstrate the physical consequences of their size through the Van der Waals equation of state, which is named after him.

Atomic-Ionic Radii: In ionic crystal structures, the ionic radius, abbreviated rion, is the radius of a monatomic ion, which is defined as the radius of the ion. The fact that neither atoms nor ions have sharp boundaries is not taken into consideration, and they are considered as if they were hard spheres with radiuses that are such that the sum of the ionic radii of the cation and anion gives the distance between the ions in a crystal lattice Ionic radii are commonly expressed in either picometers (pm) or angstroms, with 1 angstrom equal to 100 picometers (pm). 

Conclusion

A solid element’s atomic radius is half of the distance between the nuclei of identically neighbouring atoms when the element is in its solid state. Rather than having a hard spherical boundary, an atom can be thought of as a tiny, densely packed positive nucleus surrounded by an equally dense but diffusely packed negative cloud of electrons. Because of the different types of chemical bonds that can be formed between atoms, atomic radius values vary (metallic, ionic, or covalent bond). As in the case of sodium chloride, when the atoms next to each other are not identical, a portion of the observed distance between them is allocated to one type of atom and the remainder to the other type of atom.

It is more than twice as large than the ionic radius of sodium found in the compound sodium chloride because of the metallic radius of sodium atoms linked together in a chunk of sodium metal. Each sodium atom in sodium chloride has lost one electron, resulting in the formation of a sodium ion (charged atom) with a unit positive charge. Each chlorine atom, on the other hand, has received one electron, resulting in the formation of a chloride ion with a unit negative charge. The ionic radius of chlorine is roughly twice as large as the radius of a neutral chlorine atom, indicating that chlorine is a strong ion. Covalent bonds include the bond between a pair of chlorine atoms in a chlorine molecule and the bond between the carbon atoms in a diamond, to name a couple of examples. For situations like these and others like it, the atomic radius is referred to as the covalent radius.

We can only measure the potential difference between the two terminals of a cell using a voltmeter, but we can determine the value of the emf of a cell with a potentiometer.

The positive terminals of the two primary cells whose emfs are to be compared are linked in the circuit to the end A of the potentiometer wire AB, and their negative terminals are connected to a galvanometer via a two-way key a, b, c. The galvanometer’s other end is linked to a jockey J.

In the circuit between the two-way key and the galvanometer G, a resistance box, RBOX , is also connected with a key across its terminals, as shown in Fig. 4. With the help of the two-way key a, b, c, the two primary cells with emfs E1 and  E2 are connected in turn to the sliding contact J through the galvanometer G.

Using the battery E and the rheostat Rh in series across the ends of the wire AB, a steady potential difference may be maintained, with the end A being at a higher potential than the end B. It’s important to remember that emf E is greater than emf E1  and emf E1 greater than emf  E2. To bring cell E1 into the circuit, close the gap ‘a c’ in the two-way key. To get null deflection in the galvanometer, slide the jockey on the potentiometer wire. Allow it to happen at J. Make a note of AJ’s length as l1 cm . Similarly, close the gap ‘b c’ and achieve the null point J by sliding the jockey down the wire to bring E2  into the circuit.

Take note of the length AJ1 as l2 cm.

When a constant current flows through a wire of uniform thickness and material, the potential difference between any two spots on it is directly proportional to the length of the wire between the points, according to the principle of the potentiometer.

Thus,

V∝l

V=φl

Here, = potential gradient

To reduce , the length of the potentiometer wire is increased. The potentiometer becomes more sensitive and accurate when the value of   is reduced.

In case of two cells we have

E1=φl1

E2=φl2

Here, 

E1& E2= emf of the two cells

l1& l2 = Balancing lengths when E1& E2 are connected to the circuit

E1/E2 = φl1/ φl2 =l1 / l2

PROCEDURE

  1. Connect the positive terminals of the battery E and the two cells E1 and E2 to zero at the end A of the potentiometer wire, as shown in Fig. 4.
  2. Using a one-way key K1 and a rheostat, connect the negative terminal of E to the end B of the potentiometer wire.
  3. Connect the negative terminals of cells E1 and E2 to the two-way key’s terminals ‘a’ and ‘b.’
  4. Use a key K2 to shunt a resistance box RBOX . Connect one end of RBOX  to the common terminal of the two-way key.
  5. Connect the resistance box’s other end to a galvanometer with the other end connected to a jockey. To obtain null deflection in the galvanometer, the jockey can be slid on the potentiometer wire.
  6. Connect cell E1 to the circuit by putting the connector between the two-way key’s ‘a’ and ‘c’ gaps.
  7. Leave the K2 key unlocked. Reduce rheostat resistance to the minimum. Remove high resistance from the resistance box (on the order of thousands of ohms). Make contact with the jockey at the potentiometer wire’s zero end. Take note of the galvanometer’s deflection direction.
  8. Finally, move the jockey to make contact with the wire’s other end. Check to see if the galvanometer needle is deflecting in the opposite direction as it was in step 7.
  9. Connections are correct if the galvanometer needle deflects in the opposite direction in the above two scenarios. If this isn’t the case, keep an eye out for the reason. Connections could be loose, or the battery E’s emf could be lower than the cells  E1 and E2. Make the appropriate adjustments as needed.
  10. Gently slide the jockey over the potentiometer wire until the galvanometer shows no deflection. To acquire the precise position of the null (or balance) point, use the key K2 . The current going through the galvanometer is limited by the resistance in the resistance box. The current flowing through the galvanometer is minimal at the balance point; however, insertion of the key K2   short circuits the resistances and therefore raises the current. The sensitivity of balancing point identification is improved as a result of this. Take note of the wire’s length, AJ, and write it down as l1. Repeat the balancing point detection while moving the jockey in the opposite direction, and note the second value of l1.
  11. Connect E2.  to the circuit by putting a connector between the two-way key’s ‘b’ and ‘c’ gaps. Calculate J1’s .  balance point in the same way you calculated l1’s ., and record AJ1’s .  length as l2.
  12. Calculate l1/l2for each set of readings, E1 and E2., by repeating steps 6 to 11, three times while adjusting the rheostat’s contact point.
  13. Make a tabular record of your observations.

OBSERVATIONS

  1. The number of wires on the potentiometer board = …
  2. The voltmeter’s range = 0…V to … V
  3. The voltmeter’s least count = …V
  4. Potential drop across E = …V
  5. Potential drop across E1 = …V
  6. Potential drop across E2 = …V

PRECAUTIONS

  1. The electrical contact between the keys and the resistance box must be good.
  2. To avoid kinks in the potentiometer wire, the jockey should be lightly pressed on it.
  3. Before completing the task of establishing the equilibrium length with both cells, the position of the rheostat contact should not be altered.

Conclusion

The electric potential created by an electrochemical cell or by changing the magnetic field is referred to as electromotive force, or EMF. Electromotive force is frequently abbreviated as EMF. A generator or a battery is used to convert energy from one form to another. In these devices, one terminal becomes positively charged, while the other becomes negatively charged. An electromotive force is work done on a unit electric charge because of this. In 1830, English physicist Michael Faraday proposed the concept of emf for the first time. Volts is the SI unit for emf measurement. It is denoted by the symbol .

faq

Frequently asked questions

Get answers to the most common queries related to the JEE Examination Preparation.

How can one compare the emf of two cells?

Answer –A potentiometer can be used to compare the emf of two cells by c...Read full

Why is the emf of a cell always positive?

Answer –When a cell is written in shorthand notation, the emf is given a...Read full

How can a potentiometer be used to compare resistance?

Answer -A potentiometer is a tool for comparing potential differences. The gadget may be used to measure potential d...Read full

Why is a potentiometer more accurate than a voltmeter?

Answer -When measuring the emf of a cell, a potentiometer is favoured over a voltmeter since the potentiometer does ...Read full

What are the two uses of potentiometer?

Answer -The potentiometer’s uses include: Voltage divider:...Read full

Answer –A potentiometer can be used to compare the emf of two cells by connecting one cell at a time or both cells at the same time. The two-way key can be used to link one cell at a time in a circuit.

Answer –When a cell is written in shorthand notation, the emf is given a positive value if the cell reaction is spontaneous by convention. That is, if the electrode on the left pushes electrons into the external circuit and the electrode on the right pulls them out, the cell emf is displayed on the voltmeter dial.

 

Answer -A potentiometer is a tool for comparing potential differences. The gadget may be used to measure potential difference, internal resistance of a cell, and compare emf’s of two sources because the procedure includes no current flow. The voltage source being monitored does not draw any current from the potentiometer.

Answer -When measuring the emf of a cell, a potentiometer is favoured over a voltmeter since the potentiometer does not drain any current because it is a null device. The voltmeter, on the other hand, draws current from the cell.

Answer -The potentiometer’s uses include:

  1. Voltage divider: To adjust the output voltage of a voltage supply, a potentiometer can be utilised as a voltage divider.
  2. Audio control: Sliding potentiometers are often utilized as audio control devices in modem low-power audio systems.

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