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JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Physics » De Morgan’s Theorem

De Morgan’s Theorem

In this topic, we will get to know De Morgan’s theorem, verification of the theorem, proof of the theorem and examples and questions.

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A set of two laws which were given by a nineteenth-century British mathematician, Augustus De Morgan, are referred to as De Morgan’s theorem. The two laws use the rules for AND, NOT and OR functions. Using the properties of these functions, one Boolean expression can be converted from one form to the other. The first theorem states that the inversion of the product is the same as the sum of the inversions. The second theorem states that the inversion of the sum is the same as the product of the inversions. De Morgan’s theorem holds true for two or more variables. 

The first theorem

According to the first theorem given by De Morgan, when two or more variables are AND and then complemented, it is equal to the OR of the complement of each variable individually. The first De Morgan theorem can be written as:

Verifying the first De Morgan’s theorem using a truth table

Implementation of the first theorem

Proof of the first theorem

The second theorem

According to the second theorem given by De Morgan, when two or more variables are OR and then complemented, it is equal to the AND of the complement of each variable individually. The second De Morgan theorem can be written as:

Verifying the first De Morgan theorem using a truth table

Implementation of the second theorem

Proof of the second theorem

Simplification using De Morgan’s theorem

To simplify an expression using the De Morgan theorem, use the following steps:

  • Replace ‘OR’ with ‘AND’ and ‘AND’ with ‘OR’. In other words, replace ‘+’ with ‘⋅’ and ‘⋅’ with ‘+’ given in the expression. 

  • Complement each term in the expression

Example 1

Example 2

Equivalent gates using De Morgan’s theorem

To obtain equivalent gates using De Morgan’s theorem, replace the AND gate with OR gate and vice versa. Also, invert every input and output of the gate. Let us look at some examples of De Morgan’s theorem.

Example 1

Let us take a basic AND gate as follows:

To find an equivalent gate, replace the AND gate with OR gate and invert the two inputs and one output using a NOT gate as follows:

(The bubbles at the input and output represent inversion.)

Let us verify if the above expressions are equivalent using a truth table as follows:

Example 2

Let us take a basic OR gate as follows:

 

To find an equivalent gate, replace the OR gate with AND gate and invert the two inputs and one output using a NOT gate as follows:

(The bubbles at the input and output represent inversion)

Let us verify if the above expressions are equivalent using a truth table as follows:

Conclusion 

faq

Frequently Asked Questions

Get answers to the most common queries related to the JEE Examination Preparation.

What is the significance of De Morgan’s theorem?

Ans. De Morgan’s theorem is used to simplify large expressions in Boolean algebra. The law is used in Boolean alge...Read full

What are the rules used in De Morgan’s theorem?

Ans. The theorem is applied to an expression under an inversion. In the expression, ‘+’ is replaced with ‘...Read full

What is a bubbled gate?

Ans. A gate with inverted input is termed a bubbled gate. If the inputs of an AND gate are inverted, it is termed as...Read full

How can you verify De Morgan’s theorem?

Ans. The two theorems can be verified using a truth table. The values for the expression on the Left Hand Side and t...Read full

Ans. De Morgan’s theorem is used to simplify large expressions in Boolean algebra. The law is used in Boolean algebra as well as in set theory.

Ans. The theorem is applied to an expression under an inversion. In the expression, ‘+’ is replaced with ‘⋅’ and ‘⋅’ with ‘+’. Also, the inversion is broken, and each term is inverted individually.

Ans. A gate with inverted input is termed a bubbled gate. If the inputs of an AND gate are inverted, it is termed as a bubbled AND gate. Similarly, if the inputs of an OR gate are inverted, it is termed a bubbled OR gate.

Ans. The two theorems can be verified using a truth table. The values for the expression on the Left Hand Side and the expression on the Right Hand Side is obtained for each combination. It is observed that the expression on the Left Hand Side and on the Right Hand Side give the same value for each combination.

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