Access free live classes and tests on the app
Download
+
Unacademy
  • Goals
    • AFCAT
    • AP EAMCET
    • Bank Exam
    • BPSC
    • CA Foundation
    • CAPF
    • CAT
    • CBSE Class 11
    • CBSE Class 12
    • CDS
    • CLAT
    • CSIR UGC
    • GATE
    • IIT JAM
    • JEE
    • Karnataka CET
    • Karnataka PSC
    • Kerala PSC
    • MHT CET
    • MPPSC
    • NDA
    • NEET PG
    • NEET UG
    • NTA UGC
    • Railway Exam
    • SSC
    • TS EAMCET
    • UPSC
    • WBPSC
    • CFA
Login Join for Free
avtar
  • ProfileProfile
  • Settings Settings
  • Refer your friendsRefer your friends
  • Sign outSign out
  • Terms & conditions
  • •
  • Privacy policy
  • About
  • •
  • Careers
  • •
  • Blog

© 2023 Sorting Hat Technologies Pvt Ltd

Watch Free Classes
    • Free courses
    • JEE Main 2024
    • JEE Main 2024 Live Paper Discussion
    • JEE Main Rank Predictor 2024
    • JEE Main College Predictor 2024
    • Stream Predictor
    • JEE Main 2024 Free Mock Test
    • Study Materials
    • Notifications
    • JEE Advanced Syllabus
    • JEE Books
    • JEE Main Question Paper
    • JEE Coaching
    • Downloads
    • JEE Notes & Lectures
    • JEE Daily Videos
    • Difference Between
    • Full Forms
    • Important Formulas
    • Exam Tips
JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Mathematics » Single HM of n Positive Numbers

Single HM of n Positive Numbers

Study material notes on Single Harmonic Mean of ‘n’ positive numbers, Meaning of Single Harmonic Mean of ‘n’ positive numbers, Formula and derivation, practical examples, and other related concepts in detail

Table of Content
  •  

Harmonic Mean is one of the measures of average calculation. For two numbers, we can derive the Harmonic Mean of the given numbers and we can also calculate the Harmonic Mean between those given numbers. Calculating a single Harmonic Mean of ‘n’ positive numbers is similar to the Harmonic Mean of two or more numbers. Just like Arithmetic Mean, calculating Harmonic Mean is very simple. The harmonic mean of given numbers will be equal to the number of observations divided by the sum of reciprocal of the given numbers. We will discuss a stepwise approach to calculate the Single Harmonic Mean of ‘n’ positive real numbers. Let’s discuss in detail the concepts revolving around the topic and derivation formulas.

Single Harmonic Mean of n ‘positive’ numbers:

Single Harmonic Mean of n ‘positive’ numbers can be defined as the reciprocal of the Arithmetic Mean of the reciprocal of the observations. Now, let us break the definition of Harmonic Mean stated here to get a deep insight of the meaning of the terms used therein:

Let us assume that we have n number of observations and the observations are x1, x2, x3,…………………xn

Sum of Reciprocal of the observations will be:

1/x1 + 1/x2 + 1/x3+…………………………..+ 1/xn         …………………….(i)

Now, the Arithmetic Mean of reciprocal of observations can be calculated as follows:

( 1/x1 + 1/x2 + 1/x3+…………………………..+ 1/xn ) / n        ………………………….(ii)

Now, the reciprocal of Arithmetic Mean of the reciprocal of the observations will be simply the reciprocal of what we just calculated above in step (ii):

n / (1/x1 + 1/x2 + 1/x3+…………………………..+ 1/xn ) ………………………(iii)

Resulting equation (iii) is called the Harmonic Mean.

Let us understand the Harmonic Mean n ‘positive’ numbers with the help of a practical example below:

Example 1:

Let us assume that we have been given 4 observations and those are 2, 4, 6 and 10. Calculate Harmonic Mean for the given observations.

Solution:

Given Observations are:  2,4,6, 10

No. of Observations (n) = 4

Step 1:

Sum of Reciprocal of the observations will be:

1/x1 + 1/x2 + 1/x3+…………………………..+ 1/xn         …………………….(i)

Putting the values in the equation (i) above, we will get

= 1/2 + 1/4 + 1/6 + 1/10

Step 2:

The Arithmetic Mean of reciprocal of observations can be calculated as follows:

(1/x1 + 1/x2 + 1/x3+…………………………..+ 1/xn ) / n        ………………………….(ii)

Putting the values in the equation (ii) above, we will get

= (1/2 + 1/4 + 1/6 + 1/10) / 4

Step 3:

Now, the reciprocal of Arithmetic Mean of the reciprocal of the observations will be simply the reciprocal of what we just calculated above in step (ii):

n / (1/x1 + 1/x2 + 1/x3+…………………………..+ 1/xn ) ………………………(iii)

Putting the values in the equation (iii) above, we will get

= 4 / (1/2 + 1/4 + 1/6 + 1/10)

= 3.92

Hence, Harmonic Mean for the given observations = 3.92

 

Example 2:

 Insert three Harmonic Means between two numbers 15 and 15/61.

Solution:

Given Harmonic Progression (H.P.) will be as below:

15, H1, H2, H3, 15/61

a1 = 15/1 (first term)

a5 = 15/61 (fifth term)

We know that:  A1, A2,  A3,………………………….An is an A.P.

Here

A1 = 1/15 (Reciprocal of a1)

A5 = 61/15 (Reciprocal of a6)

Hence, we can calculate d from here:

a+4d = 61/15

1/15 + 4d = 61/15

d = 1

Now, as we have value of d, we can calculate all the missing values as follows:

A2 = 1/15+ 1 = 16/15

Hence H1 = 15/16

A3 = 1/15+2*1 = 31/15

H2 = 15/31

A4 = 1/15 + 3*1 = 46/15

H3 = 15/46

Properties of Mean:

  • If all the observations of the series are constant ‘K’, the mean will also be ‘K’. The same property applies for all the means be it Arithmetic Mean, Geometric Mean, or Harmonic Mean.
  • If the deviation in the series is taken from the mean, the sum of deviations from the mean will be zero.
  • If we change the origin, the same change will consequently be seen in the Mean as well.
  • Similarly, if we change the scale, the same scale change will be seen eventually in the Mean.

Conclusion:

In this article, we discussed how to calculate the single Harmonic Mean of ‘n’ positive numbers. First, we learned the derivation of the formula for Harmonic Mean of ‘n’ positive numbers. We saw practical examples for a better understanding of the formulas derived above and the application of the same in the problems. Then we discussed how the formula for Harmonic Mean between two numbers is different from the Harmonic Mean of numbers. We also discussed mathematical interpretation and relation of Harmonic Mean with other Mean formulas such as Arithmetic Mean and Geometric Mean. We hope this study material will be helpful for you and will give you a deep understanding of the topic.

faq

Frequently Asked Questions

Get answers to the most common queries related to the JEE Examination Preparation.

Question: Calculate the Harmonic Mean for the data given below:

Speed of Car No. of cars 130 ...Read full

Question: Find AM, GM and HM for 10 and 20. And Prove that AM*HM = GM2

Solution: AM = (x1 ...Read full

Question: Two cities P and Q are 360 Km apart from each other. A car goes from P to Q with a speed of 40 Km/hr and returns to P with a speed of 60 Km/hr. Find the average speed of the car. Solve using both Harmonic Mean Method and Direct method.

Solution: Using Harmonic mean: = n / (1/x...Read full

Speed of Car No. of cars
130 3
135 4
140 8
145 9
150 2

 

Solution:

xi fi fi/xi
130 3 0.0231
135 4 0.0296
140 8 0.0571
145 9 0.0621
150 2 0.0133
Total 26 0.185

Harmonic Mean = 26/0.185

H.M. = 140.35

Solution:

AM = (x1 + x2)/2 = (10+20)/2 = 15

GM = (x1*x2)1/2 = (10*20)1/2 = 14.14

HM = n / (1/x1 + 1/x2 + 1/x3+…………………………..+ 1/xn )

= 2 /(1/10+1/20)

= 13.33

AM*HM = GM2

15*13.33 = 14.14*14.14

200 = 200

LHS = RHS

Hence Proved

Solution:

Using Harmonic mean:

= n / (1/x1 + 1/x2 + 1/x3+…………………………..+ 1/xn)

= 2 / (1/40 + 1/60)

= 2 / (0.025 + 0.016667)

= 48

Using Direct Method:

Average Speed = Total Distance/ Total time taken

= (360 + 360) / 9 + 6

= 720 / 15

Hence, Average Speed of the Car = 48 Km/Hr

Total time taken:

P to Q = 360/40 = 9 hours

Q to P = 360/60 = 6 hours

Crack IIT JEE with Unacademy

Get subscription and access unlimited live and recorded courses from India’s best educators

  • Structured syllabus
  • Daily live classes
  • Ask doubts
  • Tests & practice
Learn more

Notifications

Get all the important information related to the JEE Exam including the process of application, important calendar dates, eligibility criteria, exam centers etc.

Allotment of Examination Centre
JEE Advanced Eligibility Criteria
JEE Advanced Exam Dates
JEE Advanced Exam Pattern 2023
JEE Advanced Syllabus
JEE Application Fee
JEE Application Process
JEE Eligibility Criteria 2023
JEE Exam Language and Centres
JEE Exam Pattern – Check JEE Paper Pattern 2024
JEE Examination Scheme
JEE Main 2024 Admit Card (OUT) – Steps to Download Session 1 Hall Ticket
JEE Main Application Form
JEE Main Eligibility Criteria 2024
JEE Main Exam Dates
JEE Main Exam Pattern
JEE Main Highlights
JEE Main Paper Analysis
JEE Main Question Paper with Solutions and Answer Keys
JEE Main Result 2022 (Out)
JEE Main Revised Dates
JEE Marking Scheme
JEE Preparation Books 2024 – JEE Best Books (Mains and Advanced)
Online Applications for JEE (Main)-2022 Session 2
Reserved Seats
See all

Related articles

Learn more topics related to Mathematics
Zero Vector

A zero vector is defined as a line segment coincident with its beginning and ending points. Primary Keyword: Zero Vector

ZERO MATRIX

In this article, we will discuss about the zero matrix and it’s properties.

YARDS TO FEET

In this article we will discuss the conversion of yards into feet and feets to yard.

XVI Roman Numeral

In this article we are going to discuss XVI Roman Numerals and its origin.

See all
Access more than

10,505+ courses for IIT JEE

Get subscription

Trending Topics

  • JEE Main 2024
  • JEE Main Rank Predictor 2024
  • JEE Main Mock Test 2024
  • JEE Main 2024 Admit Card
  • JEE Advanced Syllabus
  • JEE Preparation Books
  • JEE Notes
  • JEE Advanced Toppers
  • JEE Advanced 2022 Question Paper
  • JEE Advanced 2022 Answer Key
  • JEE Main Question Paper
  • JEE Main Answer key 2022
  • JEE Main Paper Analysis 2022
  • JEE Main Result
  • JEE Exam Pattern
  • JEE Main Eligibility
  • JEE College predictor
combat_iitjee

Related links

  • JEE Study Materials
  • CNG Full Form
  • Dimensional Formula of Pressure
  • Reimer Tiemann Reaction
  • Vector Triple Product
  • Swarts Reaction
  • Focal length of Convex Lens
  • Root mean square velocities
  • Fehling’s solution
testseries_iitjee
Predict your JEE Rank
.
Company Logo

Unacademy is India’s largest online learning platform. Download our apps to start learning


Starting your preparation?

Call us and we will answer all your questions about learning on Unacademy

Call +91 8585858585

Company
About usShikshodayaCareers
we're hiring
BlogsPrivacy PolicyTerms and Conditions
Help & support
User GuidelinesSite MapRefund PolicyTakedown PolicyGrievance Redressal
Products
Learner appLearner appEducator appEducator appParent appParent app
Popular goals
IIT JEEUPSCSSCCSIR UGC NETNEET UG
Trending exams
GATECATCANTA UGC NETBank Exams
Study material
UPSC Study MaterialNEET UG Study MaterialCA Foundation Study MaterialJEE Study MaterialSSC Study Material

© 2026 Sorting Hat Technologies Pvt Ltd

Unacademy
  • Goals
    • AFCAT
    • AP EAMCET
    • Bank Exam
    • BPSC
    • CA Foundation
    • CAPF
    • CAT
    • CBSE Class 11
    • CBSE Class 12
    • CDS
    • CLAT
    • CSIR UGC
    • GATE
    • IIT JAM
    • JEE
    • Karnataka CET
    • Karnataka PSC
    • Kerala PSC
    • MHT CET
    • MPPSC
    • NDA
    • NEET PG
    • NEET UG
    • NTA UGC
    • Railway Exam
    • SSC
    • TS EAMCET
    • UPSC
    • WBPSC
    • CFA

Share via

COPY