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JEE Exam » JEE Study Material » Mathematics » Law of Sines

Law of Sines

The law of sines determines the ratio of a triangle's sides, and their respective sine angles are equivalent. Sine law, sine rule, and sine formula are other terms for the law of sines.

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The rule of sines provides the link between an oblique triangle’s sides and angles (non-right triangle). In trigonometry, the law of sines and the law of cosines are critical laws for “solving a triangle.” The sine rule states that the ratios of a triangle’s side lengths to the sine of its opposing angles are equal.

Law of Sines

The ratio of a triangle’s side and matching angle is equal to the diameter of the triangle’s circumcircle. As a result, the sine law may be expressed as

a/sinA = b/sinB = c/sinC = 2R.

  • Here, a, b, and c denote the lengths of the triangle’s sides.
  • A, B, and C represent the triangle’s angles.
  • R is the radius of the triangle’s circumference.

Law of Sines Formula

The law of sines is used to calculate the lengths of a triangle’s sides in relation to the sines of consecutive angles. It is the ratio of the length of the triangle’s side to the sine of the angle created by the remaining two sides. The law of sines formula is applicable to all triangles except the SAS and SSS triangles.

It states that a/sin A = b/sin B = c/sin C, where a, b, and c are the triangle’s lengths and A, B, and C are the triangle’s angles.

This formula may be expressed in three ways: 

  • a/sinA = b/sinB = c/sinC
  • sinA/a equals sinB/b equals sinC/c
  • a/b equals sinA/sinB; a/c equals sinA/sinC; b/c equals sinB/sinC

Proof of Law of Sines Formula

Given two angles and aside, the law of sines is used to calculate the remaining sides of a triangle. This is referred to as triangulation. Additionally, it may be used when given two sides and one of the non-enclosed angles. However, in certain of these circumstances, referred to as the ambiguous case, the triangle cannot be established uniquely using the available data, and we have two alternative values for the enclosed angle. To demonstrate the sine law, consider the following two oblique triangles.

In the first triangle we have: h/b = sinA

⇒ h = b sinA 

In the second triangle we have: h/a = sinB

⇒ h = a sinB 

Additionally, sin(180o – B) = sinB.

By equating the h values in the preceding formulas, we obtain:

a sinB = b sinA

⇒ a/sinA = b/sinB

Likewise, we can infer a relationship between sin A and sin C.

asinC = csinA
⇒ a/sinA = c/sinC 

By combining the two formulas above, we obtain the sine law shown below.

a/sinA = b/sinB = c/sinC

Applications of Sine Law

The law of sines is useful for determining the missing side or angle of a triangle when all other necessary data is available. The sine law may be used to determine the following:

  • The length of a triangle’s side using ASA or AAS criteria.
  • The unknown angle of a triangle; and
  • The triangle’s area.

Law of sines in Real life

  • In real life, the law of sines is employed to determine the angle of tilt in engineering.
  • In astronomy, it is used to determine the distance between planets or stars.
  • Additionally, navigation may be quantified using the law of sines.

Law of sines and Cosines

Both the law of sines and the law of cosines are used to determine an unknown angle or side of a triangle. Let us examine the distinction between the two laws.

The sine law

It is utilized when we are given two angles and a side, or when we are given two sides and an included angle.

Cosine law

It is employed when we are given three sides or two sides plus an angle.

Conclusion

When two angles and a side are known, the rule of sines may be used to compute the remaining sides of a triangle—a process known as triangulation. Additionally, it may be employed when two sides and one of the open angles are known.

faq

Frequently asked questions

Get answers to the most common queries related to the JEE Examination Preparation.

What conditions must be met in order to apply the law of sines?

Ans: Generally, when two angles and one side or two angles and one included side are known, the law of sines is empl...Read full

What is the sine law?

Ans: According to the sine rule, if a, b, and c are the lengths of the triangle’s sides and A, B, and C are th...Read full

How can you verify vectors using the sine rule?

Ans: The magnitude of a vector’s cross product is equal to the magnitude of both vectors plus the sine of the ...Read full

What is the controversy around the Law of Sines?

Ans: One issue to consider when applying the rule of sines is the possibility of receiving two solutions for an angl...Read full

Is the Law of Sines applicable exclusively to triangles?

Ans: According to the Law of Sines, the ratio of the length of any side to the sine of its opposite angle is the sam...Read full

Ans: Generally, when two angles and one side or two angles and one included side are known, the law of sines is employed to solve the triangle. This indicates that when we have ASA (Angle-Side-Angle) or AAS (Angle-Angle-Side) criteria, we may employ the law of sines.

Ans: According to the sine rule, if a, b, and c are the lengths of the triangle’s sides and A, B, and C are the triangle’s angles; with A opposite a, etc., asinA=bsinB=csinC.

Ans: The magnitude of a vector’s cross product is equal to the magnitude of both vectors plus the sine of the angle between them. As we know, the magnitude of the cross product of two vectors equals the magnitude of both vectors multiplied by the sine of the angle between them.

Ans: One issue to consider when applying the rule of sines is the possibility of receiving two solutions for an angle variable. This is more likely to occur when two side values are supplied and an acute angle is not between the two sides. These two triangles illustrate this issue.

Ans: According to the Law of Sines, the ratio of the length of any side to the sine of its opposite angle is the same for all three sides of a triangle. This statement is true for all triangles, not only right triangles.

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