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JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Mathematics » Conditions for Minimum and Maximum Value of Parabola

Conditions for Minimum and Maximum Value of Parabola

In this article we will learn about An Overview Of Conditions For Minimum And Maximum Value Of Parabola, maximum and minimum value of quadratic function, minimum and maximum parabola and maximum value of a parabola.

Table of Content
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The vertex (h, k) is indeed the lowest point on parabola if it opens up. The smallest functional or absolute minimum value of f is referred to as k. When x Equals h, this happens. k is the highest functional or absolute maximum value of f when the parabola opens down, and it happens at x = h. Extreme functional values are the maximum and smallest functional values.

Quadratic Function Zeros

Definition: The x values that make the function value 0, also known as the x-intercepts, are the zeros of a function. Set f(x) = 0 and solve to discover the zeros of f(x).

Finding quadratic function zeros: Solving a quadratic equation is the same as finding the zeros of a quadratic function. We had three options for doing so:

1. Factor

2. Finish the Square

3. Quadratic Equation

Theorem: The discriminant of function f(x) = ax2 + bx + c is the equation b2 – 4ac. In the quadratic formula x = b, b2 – 4ac/ 2a, the discriminant is the inside of the radical.

We’ve used the discriminant to find

• If b2 – 4ac > 0, f(x) contains two zeros.

• If b2 – 4ac = 0, f(x) has a single zero.

• If b2 – 4ac 0 is true, then f(x) has no real-number zeros.

How to identify the maximum and minimum on vertical parabolas

Vertical parabolas provide a crucial piece of data: The vertex of a parabola is the lowest point on the graph, known as the minimum, or min. The vertex of a parabola is the highest point on the graph, known as the maximum, or max.

Because horizontal parabolas have no limit on how high or low they can travel, only vertical parabolas can have minimum and maximum values. The maximum height of a ball launched into the air, the maximum area of a rectangle, the lowest value of a company’s profit, and so on can all be found by finding the maximum of a parabola.

Finding a parabola’s maximum value

Consider the challenge of finding two numbers whose sum equals ten and whose product is the maximum. Two separate equations are concealed in this single sentence:

x + y = 10 xy = MAX

Solve 1 equation for one variable and substitute it into the other. If you answer the equation without using min or max, it will be the simplest. You can write y = 10 – x if x + y = 10. You can use this value to solve the other equation as follows:

(10 – x)

x = MAX

When the x is distributed on the outside, the result is 10x – x2 = MAX. This gives you a quadratic equation for which you must discover the vertex by solving the equation (which transforms the equation into the form you’re used to seeing and identifies the vertex). The maximum value is obtained by finding the vertex by completing the square.

Maximum and lowest values in the area

A local maximum is a graph point with a greater y value than all surrounding points, but not necessarily the greatest y value in the entire graph, i.e., f(x) > f(x1) for every x1 in some interval around x. A local minimum is a point on the graph with a lower y value than all other neighbouring points. The local extreme points are the sum of the local maximums and minimums.

• Relative maximum values are also known as local maximum and local minimum values.

• All absolute maximum and lowest values of f are also local maximum and minimum values.

• There is only one absolute maximum and one absolute minimum value on a graph (although it can occur at multiple x-values). Multiple local maximum & minimum values can exist in a graph.

Applications

We frequently want to increase or decrease the value of a function f. If the function f is quadratic, the y-value of the vertex is the absolute maximum (if f opens down) or absolute minimum (if f opens up).

Finding the maximum/minimum: For f(x) = ax2 + bx + c, there are two techniques to calculate the absolute maximum/minimum value:

• Write the quadratic in standard form as f(x) = a (x+ h)2 + k, where k is the absolute maximum/minimum value and x = h is the point of intersection.

• Use the formula: when x =b/2 a and its value is f(b/2a), the absolute maximum/minimum occurs.

If a > 0, the parabola opens up, and f is reduced to its smallest functional value. If a is less than zero, the parabola opens down, and f has the smallest functional value.

CONCLUSION

A parabola is a U-shaped curve that represents a quadratic function. The graph has an extreme point, termed the vertex, which is an important property. When the parabola opens up, the vertex symbolises the lowest point on the graph, or the quadratic function’s minimum value. The vertex marks the highest point on graph, or the maximum value, if the parabola expands down. The vertex is a graph turning point in either instance. The graph is also symmetric, with a vertical line called the axis of symmetry drawn through the vertex.

faq

Frequently Asked Questions

Get answers to the most common queries related to the JEE Examination Preparation.

How do you calculate a parabola's minimum and maximum values?

Ans. The y-coordinate of the vertex can be used to determine the minimum or maximum value of a parabola. You can get...Read full

What is the difference between a min and max graph?

Ans. The absolute maximum and absolute minimum are the y- coordinates (output) at the highest and lowest locations, ...Read full

How do you figure out the minimum?

Ans. Your quadratic equation will have a minimal value if it has a positive term. This minimum value can be found by...Read full

The vertex of the quadratic equation f(x)=2x^2–6x+7 is to be found. In standard form, rewrite the quadratic equation (vertex form).

Ans. The vertex’s horizontal coordinate will be h = –b/2a = -6/2(2) = 6/4= 3/2. ...Read full

Calculate the y and x intercepts of quadratic f(x)=3x^2+5x-2.

Ans. By evaluating f (0), we can obtain the y-intercept. f (0)=3(0)...Read full

Ans. The y-coordinate of the vertex can be used to determine the minimum or maximum value of a parabola. You can get the minimum or maximum value algebraically by using the formulae 

x = -b / 2a, or you can use a graph to find the vertex. This formula would give you the vertex’s x-coordinate.

 

Ans. The absolute maximum and absolute minimum are the y- coordinates (output) at the highest and lowest locations, respectively. To find absolute maxima and minima in a graph, we must first examine it to see where it reaches its lowest and highest points on the function’s domain.

Ans. Your quadratic equation will have a minimal value if it has a positive term. This minimum value can be found by graphing the curve or using one of two equations. You can obtain the minimum value using the expression min = c – b2/4a if the equation is in the form y = ax2 + bx + c.

 

Ans. The vertex’s horizontal coordinate will be h = –b/2a = -6/2(2) = 6/4= 3/2.

The vertex’s vertical coordinate will be k = f(h)= f (3/2) = 2(3/2)2-6(3/2)+7=5/2.

The stretch factor in standard form will be the same as an in the original quadratic:

f(x)=ax2+ bx + c

(x)=2x2− 6x +7

Rewrite f(x) = 2(x- 3/2)2 + 5/2 using the vertex’s h and k values.

Ans. By evaluating f (0), we can obtain the y-intercept.

f (0)=3(0)

2+ 5(0) − 2 = −2

The y-intercept is located at (0,2).

We find all f(x)=0 solutions for the x-intercepts.

0 = 3x2+5x−2

In this example, factoring the quadratic provides the simplest solution approach.

0=(3x−1) (x+2) 

0 = 3x−1

x = 1/3                           

Or, 0 = x+2 

  • x = −2

Hence, (13,0) and (2,0) are the x-intercepts, respectively.

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