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JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Mathematics » Complex Numbers in Algebra

Complex Numbers in Algebra

In this article, we will study the Complex Number in algebra, definition, and the root of the complex number

Table of Content
  •  

We know that the square root of 4 is 2 but we cannot calculate the square root of -4 and from here a new concept generates and that leads to the new concept in mathematics that is a complex number.

Definition

It is the sum of a real number and an imaginary number and is of the form of a + ib which is usually represented by Z.

In Mathematics, a complex Number is an algebraic expression that includes the factor 

i = √(-1).

And “i” is called an iota.

A complex number are of the form Z=a=ib,  has two parts,

  • Real part: The real part of given Z is “a” and is denoted by Re(Z)=a.

  • Imaginary Part.: The imaginary part of given Z is “b” and is denoted by Im(Z)=b

Addition of complex numbers

Let us take two complex numbers to say,

 z1 = a + ib and  z2 = c + id,

Then the sum of these two complex numbers is:

z1+ z2 = (a + ib) + (c + id)

=(a + c) + i(b + d)

Therefore, 

z1 + z2 = Re (z1+ z2) + Im(z1+ z2)

Difference of complex numbers

Let us take two complex numbers to say,

 z1= a + ib and  z2 = c + id, 

Then the difference of these two complex numbers is:

z1- z2= (a + ib) – (c + id)

= (a – c) + i (b – d)

Therefore, 

z1 – z2 = Re(z1 – z2 ) + Im(z1 – z2)

Note:

  • Pure Real Number: When the imaginary part of the complex number is Zero(0) 

Example: 4, 8, 5 etc

  • Pure Imaginary Number: When the real part of the complex number is Zero(0)

Example: 4i, 9i, 10i etc

  • The addition of complex numbers can be another complex number.

  • The subtraction of complex numbers can be another complex number.

Roots of Complex Number

Follow the simple two-step to find the roots of the complex number

  1. Convert the given Complex number in the Polar form.

Let us take a complex number Z=a+ib

Now, convert this into the polar form we get,

Z= r(cos + i sin )

  1. Solve by Applying De Moivre’s Theorem.

For any Complex Number Z and any integer n, 

rcos +isin n=rn(cos n +isin n )

Conclusion

A complex number is a number that has two real parts and an imaginary part. A complex number can also be converted into polar form, [Z=a+ib= r (cos + i sin )] and the root of the complex number can be calculated by first converting the complex number into its polar form and then applying De Moivre’s Theorem.

faq

Frequently asked questions

Get answers to the most common queries related to the IIT JEE Examination Preparation.

Write the definition of the complex number?

Ans.  It is the sum of a real number and an imaginary number and is of the form of a + ib which is usuall...Read full

Convert Z=3+i4 into polar form.

Ans.  ...Read full

Evaluate (1+Evaluate (1+√3i)2022.3i)2022.

Ans. ...Read full

Ans.  It is the sum of a real number and an imaginary number and is of the form of a + ib which is usually represented by Z. where a and b are integer.

Ans. 

Ans.

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