Access free live classes and tests on the app
Download
+
Unacademy
  • Goals
    • AFCAT
    • AP EAMCET
    • Bank Exam
    • BPSC
    • CA Foundation
    • CAPF
    • CAT
    • CBSE Class 11
    • CBSE Class 12
    • CDS
    • CLAT
    • CSIR UGC
    • GATE
    • IIT JAM
    • JEE
    • Karnataka CET
    • Karnataka PSC
    • Kerala PSC
    • MHT CET
    • MPPSC
    • NDA
    • NEET PG
    • NEET UG
    • NTA UGC
    • Railway Exam
    • SSC
    • TS EAMCET
    • UPSC
    • WBPSC
    • CFA
Login Join for Free
avtar
  • ProfileProfile
  • Settings Settings
  • Refer your friendsRefer your friends
  • Sign outSign out
  • Terms & conditions
  • •
  • Privacy policy
  • About
  • •
  • Careers
  • •
  • Blog

© 2023 Sorting Hat Technologies Pvt Ltd

    • Free courses
    • JEE Main 2024
    • JEE Main 2024 Live Paper Discussion
    • JEE Main Rank Predictor 2024
    • JEE Main College Predictor 2024
    • Stream Predictor
    • JEE Main 2024 Free Mock Test
    • Study Materials
    • Notifications
    • JEE Advanced Syllabus
    • JEE Books
    • JEE Main Question Paper
    • JEE Coaching
    • Downloads
    • JEE Notes & Lectures
    • JEE Daily Videos
    • Difference Between
    • Full Forms
    • Important Formulas
    • Exam Tips
JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Chemistry » Van der Waals Equation

Van der Waals Equation

This article is all about Van der Waals equation, its derivation and it’s relation with the pressure and volume.

Table of Content
  •  
In the year 1873 Johannes Diderik van der Waals derived the Van der Waals equation. This equation is actually a revised version of ideal gas law. According to ideal gas law, the gases consist of point masses that undergo perfectly elastic collision. This law was not able to clearly explain the behaviour of real gases. So, this equation was revised and it now helps in defining the physical state of real gases. Van Der Waals equation takes into account the molecular size and molecular interaction forces like attractive and repulsive forces. This equation relates with a relationship between pressure, volume, temperature and amount of real gases. Therefore, for ‘ n ’ moles of a real gas the equation can be written as:

Units of Van der Waals Equation

  • ‘a’ has a unit of atm lit² mol⁻².
  • ‘b’ has a unit of litre mol⁻¹.

Van der Waals Equation Derivation

This equation is derived on the basis of correcting pressure and volume of the ideal gases given via Kinetic Theory of gases, and is also based upon the potential of  the particles.

Van der Waals equation of State as seen real gases

The kinetic theory of ideal gases presumes the gaseous particles like:
  • Point masses that have no volume.
  • Having no interactions is believed to be independent.
  • They are able to go through perfectly elastic collisions.
Previously Van der Waals presumed the gaseous particles:
  • Very hard sphere like
  • Having definite volume and cannot be compressed after a certain limit
  • Two particles when they are in close proximity to each other interact, and creates an exclusive spherical volume around them.

Volume Correction as seen in Van der Waals Equation

Since the particles have a definite volume so the volume available for their movement does not represent the entire container volume but less. Thus, the volume in ideal gas is overvalued and it needs to be reduced for real gases. ‘ VR ’ represents the volume of real gas which is equals to ‘ VI ’ which is the volume of an ideal gas or the volume of container, minus the correction factor (b):
V R = V I – b
Van der Waal observed that the two hard sphere particles could come as close as to each other, and would not allow any other particle to enter in that volume. The radius of these two particles is found to be ‘ 2r ‘. Thus the volume correction for ‘ n ‘ number of particles can be represented as:
b = 4 NA . 4/3 π.r3
Here, NA represents the Avogadro’s number and r is the radius of the particles.

Pressure Correction as seen in Van der Waals Equation

Gaseous particles are able to interact but the particles present inside, among them the interaction gets cancelled. Whereas the particles that are present on the surface or near the walls of the container do not contain particles above the surface and on the walls. This results in net interactions in the bulk molecules towards the bulk which is located away from the walls and the surface. The molecules that experience the  interactions away from the wall, hit the wall with little force and pressure. Therefore in real gases the particles have lower pressure than those shown by ideal gases. The equation for correction in pressure can be written as:
Pi = Pr + an2 / V2
After substituting the pressure and volume corrections in ideal gas equation, gives us the Van der Waals Equation for real gases :
(P + an2 / V2)(V – nb) = nRT
The constants a and b represent the characteristics of the individual gases. If both the gases are found to be ideal or if they behave ideally then the value of both the  constants will be zero.

Relation between Ideal Gas and Van der Waals Equation

The ideal gas equation is written as PV = nRT and Van der Waals Equation can be written as (P + an2 / V2)(V – nb) = nRT . At constant temperature a decrease in pressure and an increase in volume can be seen. So at low pressure volume will be larger, thus the correction factor in pressure becomes very small.
Volume of the gas will become larger as compared to the volume of the molecules (i.e. n, b) therefore the volume correction will also become very small.
Since the correction factor becomes small the pressure and volume of real gases becomes equal to that of the ideal gases. Also at low pressure and high temperatures all real gases behave like that of ideal gases.

Advantages of Van der Waals Equation

  • This equation helps in predicting the behaviour of gases better than those of ideal gas equations.
  • Not only this equation is valid for gases but also for all fluids.
  • This equation helps in calculating the critical conditions of liquefaction and to derive an equation of Principle of Corresponding States.

Disadvantages of Van der Waals Equation

  • Only above critical temperatures this equation can give more accurate results of real gases.
  • The results can also be accepted below the critical temperatures.
  • Below the critical temperatures this equation completely failed in the transition phase of gas to the liquid.

Conclusion

Our conclusion is that the Van der Waals Equation of State gives a critical point since the equation has a unique solution. In the equation V is very large, so (a/V2 ) becomes very small therefore it can be neglected. b can also be neglected in response to V. Thus, Van der Waals Equation now becomes PV = RT this is the main reason why at low pressure real gases behave like ideal gases.
faq

Frequently asked questions

Get answers to the most common queries related to the JEE Examination Preparation.

Q1. Define Van der Waals equation.

Ans. It is an equation of state which expands the ideal gas law to include the effects of interaction among the mole...Read full

Q2. Write the equation for an ideal gas.

Ans. The ideal gas equation is written as: PV = nRT

Q3. Define Compressibility Factor.

Ans. It measures the deviation of a real gas from an ideal gas behaviour. Its formula for calculation is written as-...Read full

Q4. If at low pressure the Van der Waals Equation can be written as (P + a/V2)V = RT, the compressibility factor can be written as?

Ans. The compressibility factor can be written as (1-a/RTV).

Q5. At high temperatures and low pressure the Van der Waals Equation can be reduced to?

Ans. At high temperatures and low pressure V is greater as compared to b and ( a/V...Read full

Ans. It is an equation of state which expands the ideal gas law to include the effects of interaction among the molecules of a gas

Ans. The ideal gas equation is written as: PV = nRT

Ans. It measures the deviation of a real gas from an ideal gas behaviour. Its formula for calculation is written as-Z=p/⍴RT. The value of this factor remains one for ideal gases, it can be lesser or more than one.

Ans. The compressibility factor can be written as (1-a/RTV).

Ans. At high temperatures and low pressure V is greater as compared to b and ( a/V2 ) becomes negligible as compared to pressure. Thus the equation is reduced to PV = RT.

Crack IIT JEE with Unacademy

Get subscription and access unlimited live and recorded courses from India’s best educators

  • Structured syllabus
  • Daily live classes
  • Ask doubts
  • Tests & practice
Learn more

Notifications

Get all the important information related to the JEE Exam including the process of application, important calendar dates, eligibility criteria, exam centers etc.

Allotment of Examination Centre
JEE Advanced Eligibility Criteria
JEE Advanced Exam Dates
JEE Advanced Exam Pattern 2023
JEE Advanced Syllabus
JEE Application Fee
JEE Application Process
JEE Eligibility Criteria 2023
JEE Exam Language and Centres
JEE Exam Pattern – Check JEE Paper Pattern 2024
JEE Examination Scheme
JEE Main 2024 Admit Card (OUT) – Steps to Download Session 1 Hall Ticket
JEE Main Application Form
JEE Main Eligibility Criteria 2024
JEE Main Exam Dates
JEE Main Exam Pattern
JEE Main Highlights
JEE Main Paper Analysis
JEE Main Question Paper with Solutions and Answer Keys
JEE Main Result 2022 (Out)
JEE Main Revised Dates
JEE Marking Scheme
JEE Preparation Books 2024 – JEE Best Books (Mains and Advanced)
Online Applications for JEE (Main)-2022 Session 2
Reserved Seats
See all

Related articles

Learn more topics related to Chemistry
Zeolites

Aluminium silicate zeolites are microporous three-dimensional crystalline solids. Zeolites have small, fixed-size openings that allow small molecules to pass through easily but not larger molecules; this is why they are sometimes referred to as molecular sieves.

XeF6 Molecular Geometry and Bond Angles

In this article, we will learn about the XeF6 Molecular Geometry And Bond Angles in detail. We also learn the importance of XeF6 molecular geometry and bond angles importance and much more about the topic in detail.

XeF4 Molecular Geometry and Bond Angeles

A general overview of Lewis Structure, XeF4 Molecular Geometry and bond Angles meaning, valuable XeF4 Molecular Geometry and bond angle questions.

XeF2 Molecular Geometry and Bond Angles

Let us learn about the molecule XeF2, its molecular geometry and bond examples, and XeF2 Lewis structure.

See all
Access more than

10,505+ courses for IIT JEE

Get subscription
Company Logo

Unacademy is India’s largest online learning platform. Download our apps to start learning


Starting your preparation?

Call us and we will answer all your questions about learning on Unacademy

Call +91 8585858585

Company
About usShikshodayaCareers
we're hiring
BlogsPrivacy PolicyTerms and Conditions
Help & support
User GuidelinesSite MapRefund PolicyTakedown PolicyGrievance Redressal
Products
Learner appLearner appEducator appEducator appParent appParent app
Popular goals
IIT JEEUPSCSSCCSIR UGC NETNEET UG
Trending exams
GATECATCANTA UGC NETBank Exams
Study material
UPSC Study MaterialNEET UG Study MaterialCA Foundation Study MaterialJEE Study MaterialSSC Study Material

© 2026 Sorting Hat Technologies Pvt Ltd

Unacademy
  • Goals
    • AFCAT
    • AP EAMCET
    • Bank Exam
    • BPSC
    • CA Foundation
    • CAPF
    • CAT
    • CBSE Class 11
    • CBSE Class 12
    • CDS
    • CLAT
    • CSIR UGC
    • GATE
    • IIT JAM
    • JEE
    • Karnataka CET
    • Karnataka PSC
    • Kerala PSC
    • MHT CET
    • MPPSC
    • NDA
    • NEET PG
    • NEET UG
    • NTA UGC
    • Railway Exam
    • SSC
    • TS EAMCET
    • UPSC
    • WBPSC
    • CFA

Share via

COPY