A similar mixture of compounds consists of physical properties that are straightforwardly connected to the element’s quality. The interactions in-between the molecules of the components do not vary from the interactions in-between the molecules of each component are known as the ideal solution. The molecules in the ideal solution apply forces on one another. For all levels of concentration and temperatures, the solutions follow Raoult’s Law. This only works for the ideal solution. In some other cases, it works fairly for solvent in the dilute solution, but as a result, the decrease in vapour pressure is greater than the calculation of Raoult’s Laws.
The ideal solution R and S is formed when R-S interactions in the solution are similar to the R-Rand S-S interactions. It should be of an equal type of component that will interact with itself and the other component. Their ideal solution always obeys Raoult’s Law.
The Characteristics of Ideal Solution
So here, the equality between the intermolecular forces of attraction can help us to secure an ideal solution.
Francois Marte Raoult, a French Chemist. In 1986, formulated a connection between a mole of a fraction of volatile liquids and partial pressure.
The limited vapour pressure of a solvent present in a solution is equivalent to the vapour pressure of a pure solvent which is increased by the mole fraction of the solution, which is what Raoult’s Law infers.
PSolution = Χsolvent PSolvent
Whereas;
An antifreeze solution is prepared from 222.6 g of ethylene glycol (C2H6O2) and 200 g of water. Calculate the morality of the solution. If the density of the solution is 1.072 g mL-1, then what shall be the molarity of the solution?
Ans: Calculation of Molality :
Mass of ethylene glycol = 222.6 (Given)
Molar mass of ethylene glycol [C2H4(OH)2]
= 2 X 12 + 6 x 1 + 2 x 16 = 62
Therefore moles of ethylene glycol
= 222.6g / 62 gmol-1 = 3.59 mol
Mass of water = 200g (Given)
Therefore molality of the solution is = (moles of ethylene glycol / mass of water) x 1000
= (3.59 / 200) x 1000 = 17.95 m
Calculation of Molarity:
Moles of ethylene glycol = 3.59 mol (already calculated)
Total Mass of solution = 200 + 222.6 = 422.6g
Volume of solution = mass / density volume
= 422.6 / 1.072 = 394.22 ml
now molarity of the solution is = (moles of ethylene glycol / volume of solution) x 1000
= (3.59 / 394.22) x 1000
= 9.11 M
At equilibrium:
PA = P°A xA ,PB = P°B xB
There are also some limitations of Raoult’s Law and they are as follows;
Many of the times, an ideal solution contains physical properties which are almost related to the properties of the pure components. Few properties are as follows;
ΔmixH=0
ΔmixV=0
Securing an accurate and well-balanced ideal solution can be rare, but in some of the solutions, we can see a possible behaviour of displaying an ideal solution. For example,
The partial vapour pressure of a solvent in a solution (or mixture) is identical to or equal to the vapour pressure of a pure solvent increased by the mole fraction of the solution.
PA ∝ XA
It is the solution that doesn’t obey Raoult’s Law at all the levels of temperatures and concentrations. It is very much dissimilar from the ideal solution and referred to as Non- ideal solution.
Raoult’s law does not apply to all kinds of solutions but only ideal solutions. An ideal solution has solvent-solute interactions the same as the solvent-solvent or solute-solute interaction.
In this of Raoult’s Law – Ideal solutions, we understood that the main purpose of Raoult’s Law is the ideal solution. The Force of attraction between the solute and solvent is similar to the force of attraction between solvent-solute. It implies that the total vapour pressure over a solution can be related to a mole of the fraction of any one component. Raoult’s Law only works fairly for the ideal solutions. The ideal solution obeys Raoult’s Law, whereas the non-ideal reaction does not obey Raoult’s Law and contains different molecules between the solute and solvent.