Access free live classes and tests on the app
Download
+
Unacademy
  • Goals
    • AFCAT
    • AP EAMCET
    • Bank Exam
    • BPSC
    • CA Foundation
    • CAPF
    • CAT
    • CBSE Class 11
    • CBSE Class 12
    • CDS
    • CLAT
    • CSIR UGC
    • GATE
    • IIT JAM
    • JEE
    • Karnataka CET
    • Karnataka PSC
    • Kerala PSC
    • MHT CET
    • MPPSC
    • NDA
    • NEET PG
    • NEET UG
    • NTA UGC
    • Railway Exam
    • SSC
    • TS EAMCET
    • UPSC
    • WBPSC
    • CFA
Login Join for Free
avtar
  • ProfileProfile
  • Settings Settings
  • Refer your friendsRefer your friends
  • Sign outSign out
  • Terms & conditions
  • •
  • Privacy policy
  • About
  • •
  • Careers
  • •
  • Blog

© 2023 Sorting Hat Technologies Pvt Ltd

Watch Free Classes
    • Free courses
    • JEE Main 2024
    • JEE Main 2024 Live Paper Discussion
    • JEE Main Rank Predictor 2024
    • JEE Main College Predictor 2024
    • Stream Predictor
    • JEE Main 2024 Free Mock Test
    • Study Materials
    • Notifications
    • JEE Advanced Syllabus
    • JEE Books
    • JEE Main Question Paper
    • JEE Coaching
    • Downloads
    • JEE Notes & Lectures
    • JEE Daily Videos
    • Difference Between
    • Full Forms
    • Important Formulas
    • Exam Tips
JEE Main 2026 Preparation: Question Papers, Solutions, Mock Tests & Strategy Unacademy » JEE Study Material » Chemistry » Graphical Representation of Charles Law

Graphical Representation of Charles Law

Charles’ Law gives the connection between the volume filled by gas and its absolute temperature. Let us understand the graphical representation of Charles’ Law.

Table of Content
  •  

Charles’ law, a gas law, states that in ideal gas mixtures, the pressure is inversely proportional to the volume of a gas. The law takes its name after the French scientist, Jacques Charles Lilienfeld.  

Charles’ law is important in several fields of science, including astronomy, aviation, chemistry, and chemistry. To satisfy Charles’ law, the density of the gas must be constant.

Let us take a closer look at Charles’ law and graphical representation Of Charles’ Law.

Charles’ Law

According to Charles’ law, in a closed system, the volume of a gas is directly proportional to its temperature (in Kelvin). As a result, this law describes the link between the gas’s temperature and volume. We can use the following formula to express Charles’ law.

V ∝ T 

Where,

V = volume of gas

T = temperature of the gas in Kelvin

Graphical Representation of Charles’ Law

Mathematical Expression of Charles’ Law

V1 / T1 = V2 / T2

Furthermore,

V1 / T1 = V2 / T2 ⇒ V/T = constant= K2

So, 

V= K2T

As a result, the gas’s pressure, volume, and unit of volume determine the value of K2.

cha

Charles’ Law: Discovery and Naming

The law’s name is a tribute to the French mathematician, physicist, inventor, and balloonist Jacques Alexandre César Charles. 

French chemist and physicist Joseph Louis Gay-Lussac wrote a paper outlining how gases expand when heated. He published it just a few days after the first human-crewed hot air balloon flight in 1802. 

In 1787, Charles experimented with filling five identical containers with various gases. After that, he raised the temperature of the containers to 80 degrees Celsius. He then saw that all gases had grown in volume by the same amount. Charles deduced that the volume of gas increases linearly with the absolute temperature of that gas under constant pressure

Gay-Lussac mentioned this experiment in his paper, attributing it to Jacques Charles’ unpublished work from the 1780s. That is why in honour of Charles, Gay-Lussac titled the statute ‘Charles Law.’

Application of Charles’ Law in Real Life

This law has several applications in everyday life. 

Inflated Items

Suppose you are outside on a cold day with a balloon. You will notice that the balloon crumbles. On the other hand, the balloon regains its shape when placed in a warm environment. What causes this to happen? 

This phenomenon occurs because the volume reduces when the temperature drops on a chilly day. Now, according to Charles’ Law, the temperature rises as soon as you enter a heated room. Likewise, as the temperature rises, the volume rises as well. As a result, the balloon returns to its former shape.

This behaviour is true of any inflated item. That is why you should check the pressure in your automobile tires while going outside on chilly days.

Baking

Our kitchens are no exception to Charles’ Law. Have you ever tried your hand at baking? 

Yes? 

Then, you are probably familiar with the most popular ingredient in the process: yeast. Baking yeast is commonly used to generate fluffy baked items. It induces the release of carbon dioxide bubbles. 

When the temperature rises, the carbon dioxide bubbles expand, acting as a leavening agent, causing the bread items to puff up. With a higher temperature, the carbon dioxide bubbles will expand even more.

Hot Air Balloons

You may have been curious about how a hot air balloon works. 

Temperature and volume are precisely proportional to each other, according to Charles’ Law. When you heat a gas, its density decreases, and it expands. Warm air is less dense than cold air, which is lighter. Warm air also has less mass per unit volume. That is why warm air rises above cold air.

The hot air balloon uses the same principle. The air inside the balloon is heated, causing its temperature to increase compared to the surrounding air. And the balloon rises up.

Pop-Up Turkey Timer

Charles’ rule also governs the operation of the Pop-Up Turkey Timer (Thermometer). Let us look at how it does so! 

If you recall, Charles’ law says that gases expand when heated. The Pop-Up Turkey Timer works on the same concept. When you roast your turkey in an oven, you insert the tool inside the turkey. The gas inside the thermometer expands as the temperature rises. When the timer beeps, it is time to remove the turkey from the oven.

Conclusion

This graphical representation of Charles’ Law notes discusses the law and its history. It also discusses the applications of Charles’ Law. In this gas law, we consider the density of the gas as constant. We also plotted the law on the graph.

faq

Frequently asked questions

Get answers to the most common queries related to the IIT JEE Examination Preparation.

How do you use Charles’ Law formula?

Ans. We can use the equation:  V...Read full

What is the solution to the Charles’ Law formula?

Ans. According to the equation of Charles’ Law, V ...Read full

How does Charles’ Law get calculated?

Ans. We can compute Charles’ Law as follows: Le...Read full

What cannot be changed about Charles’ Law?

Ans. Charles’ Law maintains a constant level of pressure. If the pressure remains constant, the volume of ...Read full

Ans. We can use the equation:

 V1T1=V2T2

Charles’ Law is used to compute the unknown volume or temperature of a reaction or process under constant pressure (at constant pressure).

Ans. According to the equation of Charles’ Law,

V ∝ T

The mathematical formulation for Charles’ Law will be:

kT = V

k = V/T

Where, 

V denotes the gas’s volume.

T is the Kelvin temperature of the gas.

The non-zero constant is k.

Ans. We can compute Charles’ Law as follows:

Let V1 denote the volume of a gas at T1. If the temperature of the gas is raised to T2 and the pressure remains constant, the volume will rise to V2. 

As a result, according to the law, 

V1T1=V2T2 (at constant mass and pressure)

Ans. Charles’ Law maintains a constant level of pressure. If the pressure remains constant, the volume of the gas is proportional to the temperature, according to Charles’ Law.

Crack IIT JEE with Unacademy

Get subscription and access unlimited live and recorded courses from India’s best educators

  • Structured syllabus
  • Daily live classes
  • Ask doubts
  • Tests & practice
Learn more

Notifications

Get all the important information related to the JEE Exam including the process of application, important calendar dates, eligibility criteria, exam centers etc.

Allotment of Examination Centre
JEE Advanced Eligibility Criteria
JEE Advanced Exam Dates
JEE Advanced Exam Pattern 2023
JEE Advanced Syllabus
JEE Application Fee
JEE Application Process
JEE Eligibility Criteria 2023
JEE Exam Language and Centres
JEE Exam Pattern – Check JEE Paper Pattern 2024
JEE Examination Scheme
JEE Main 2024 Admit Card (OUT) – Steps to Download Session 1 Hall Ticket
JEE Main Application Form
JEE Main Eligibility Criteria 2024
JEE Main Exam Dates
JEE Main Exam Pattern
JEE Main Highlights
JEE Main Paper Analysis
JEE Main Question Paper with Solutions and Answer Keys
JEE Main Result 2022 (Out)
JEE Main Revised Dates
JEE Marking Scheme
JEE Preparation Books 2024 – JEE Best Books (Mains and Advanced)
Online Applications for JEE (Main)-2022 Session 2
Reserved Seats
See all

Related articles

Learn more topics related to Chemistry
Zeolites

Aluminium silicate zeolites are microporous three-dimensional crystalline solids. Zeolites have small, fixed-size openings that allow small molecules to pass through easily but not larger molecules; this is why they are sometimes referred to as molecular sieves.

XeF6 Molecular Geometry and Bond Angles

In this article, we will learn about the XeF6 Molecular Geometry And Bond Angles in detail. We also learn the importance of XeF6 molecular geometry and bond angles importance and much more about the topic in detail.

XeF4 Molecular Geometry and Bond Angeles

A general overview of Lewis Structure, XeF4 Molecular Geometry and bond Angles meaning, valuable XeF4 Molecular Geometry and bond angle questions.

XeF2 Molecular Geometry and Bond Angles

Let us learn about the molecule XeF2, its molecular geometry and bond examples, and XeF2 Lewis structure.

See all
Access more than

10,505+ courses for IIT JEE

Get subscription
Challenge Yourself Everyday
Attempt 2023’s and previous year’s JEE Main
Download Important Formulas pdf
Attempt Free Test Series for JEE Main 2023

Trending Topics

  • JEE Main 2024
  • JEE Main Rank Predictor 2024
  • JEE Main Mock Test 2024
  • JEE Main 2024 Admit Card
  • JEE Advanced Syllabus
  • JEE Preparation Books
  • JEE Notes
  • JEE Advanced Toppers
  • JEE Advanced 2022 Question Paper
  • JEE Advanced 2022 Answer Key
  • JEE Main Question Paper
  • JEE Main Answer key 2022
  • JEE Main Paper Analysis 2022
  • JEE Main Result
  • JEE Exam Pattern
  • JEE Main Eligibility
  • JEE College predictor

JEE Coaching Centres

  • JEE Coaching in Nagpur
  • JEE Coaching in Ranchi
  • JEE Coaching in Gorakhpur
  • JEE Coaching in Bhubaneswar
  • JEE Coaching in Vijayawada
  • JEE Coaching in Dehradun
  • JEE Coaching in Indore
  • JEE Coaching in Gurugram
  • JEE Coaching in Muzaffarpur
  • JEE Coaching in Varanasi
  • JEE Coaching in Jammu
  • JEE Coaching in Kolhapur
  • JEE Coaching in Bikaner
  • JEE Coaching in Delhi Lajpat Nagar
Predict your JEE Rank
.
Company Logo

Unacademy is India’s largest online learning platform. Download our apps to start learning


Starting your preparation?

Call us and we will answer all your questions about learning on Unacademy

Call +91 8585858585

Company
About usShikshodayaCareers
we're hiring
BlogsPrivacy PolicyTerms and Conditions
Help & support
User GuidelinesSite MapRefund PolicyTakedown PolicyGrievance Redressal
Products
Learner appLearner appEducator appEducator appParent appParent app
Popular goals
IIT JEEUPSCSSCCSIR UGC NETNEET UG
Trending exams
GATECATCANTA UGC NETBank Exams
Study material
UPSC Study MaterialNEET UG Study MaterialCA Foundation Study MaterialJEE Study MaterialSSC Study Material

© 2026 Sorting Hat Technologies Pvt Ltd

Unacademy
  • Goals
    • AFCAT
    • AP EAMCET
    • Bank Exam
    • BPSC
    • CA Foundation
    • CAPF
    • CAT
    • CBSE Class 11
    • CBSE Class 12
    • CDS
    • CLAT
    • CSIR UGC
    • GATE
    • IIT JAM
    • JEE
    • Karnataka CET
    • Karnataka PSC
    • Kerala PSC
    • MHT CET
    • MPPSC
    • NDA
    • NEET PG
    • NEET UG
    • NTA UGC
    • Railway Exam
    • SSC
    • TS EAMCET
    • UPSC
    • WBPSC
    • CFA

Share via

COPY