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Concentration in Terms of Molarity

Molar concentration (also known as molarity, quantity concentration, or substance concentration) is a measurement of a chemical species' concentration in a solution in terms of the amount of substance per unit volume of solution.

One of the most popular measures used to quantify the concentration of a solution is molarity (M), which shows the number of moles of solute per litre of solution (moles/Liter).

Molarity is a unit of measurement that can be used to determine the volume of a solvent or the amount of a solute.

The formula C1V1 = C2V2, 

where, c is concentration and V is volume, can be used to describe the relationship between two solutions containing the same amount of moles of solute.

  • Dilution is the process of making a solution less concentrated by adding more solvent to it.
  • The SI unit is a new version of the metric system that is widely used in science.
  • molarity: The number of moles of solute per litre of solution, which represents the concentration of a chemical in solution.

The amount of solute in a solution expressed as a percentage.

In chemistry, the molarity (M) of a solution, which is the number of moles of solute per litre of solution, is commonly used to express its concentration. The molar concentration (ci) is derived by the number of moles of solute (ni) by the total volume (V) of the:

  ci = ni / V

Mol/m3 is the SI unit for molar concentration. Mol/L, on the other hand, is a more commonly used unit for molarity. One Molar, or 1 M, is a solution that contains 1 mole of solute per 1 litre of solution (1 mol/L). The following equation can be used to convert mol/L to mol/m3.

1 mol/L = 1 mol/dm3 = 1 mol dm-3 = 1 M = 1000 mol/m3

Molarity Calculation

The number of moles of solute must be divided by the total litres of solution produced to determine the molarity of a solution. If the amount of solute is given in grams, we must first determine the number of moles of solute using the solute’s molar mass, and then use the number of moles and total volume to get the molarity.

Using Molarity and Moles to Calculate Volume

Given the molarity of the solution, we can also determine the volume required to achieve a specified mass in grams. This is beneficial for specific solutes that are difficult to mass with a balance. Diborane (B2H6), for example, is a helpful organic synthesis reactant but is also highly poisonous and combustible. When diborane is dissolved in tetrahydrofuran, it is safer to use and transport (THF).

To get 4.0 g of BH3, how many millilitres of a 3.0 M BH3-THF solution are needed?

To begin, divide the mass by the molecular weight to convert grammes of BH3 to moles.

4.0 g BH3 / 13.84g mole-1 BH3=0.29 moles BH3

We can use this and the stated molarity (3.0 M) to determine the volume required to obtain 4.0 g once we know we need 0.29 moles of BH3.

ci=ni/V

3.0 M=0.29moles BH3  / V 

V=0.1L

Now that we know there are 4.0 g of BH3 in 0.1 L, we can calculate that 100 mL of solution is required to obtain 4.0 g of BH3.

Dilution

Dilution is the process of lowering a solute’s concentration in a solution by adding more solvent. The equation C1V1 = C2V2 represents this relationship, with c1 and c2 representing the initial and final concentrations, and V1 and V2 representing the initial and final volumes of the solution.

Example

A scientist has a 5.0 M hydrochloric acid (HCl) solution on hand, but his new experiment calls for 150.0 mL of 2.0 M HCl. To make 150.0 mL of 2.0 M HCl, how much water and how much 5.0 M HCl should the scientist use?

C1V1 = C2V2

The concentration and volume of the initial solution, which is 5.0 M HCl, are c1 and V1. The concentration and volume of the desired solution, or 150.0 mL of 2.0 M HCl solution, are c2 and V2. Because both sides of the calculation utilise millilitres, there is no need to convert the volume to litres just yet. Therefore:

 (5.0 M HCl ) ( V1 ) = ( 2.0 M HCl ) ( 150.0 mL )

V1 = 60.0 mL of 5.0 M HCl

If 60.0 mL of 5.0 M HCl is used to generate the desired solution, the amount of water required to dilute it to the right molarity and volume can be calculated as follows:

150.0 millilitres – 60.0 millilitres = 90.0 millilitres

To make 150.0 mL of 2.0 M HCl, the scientist will require 60.0 mL of 5.0 M HCl and 90.0 mL of water.

Conclusion

One of the most popular measures used to quantify the concentration of a solution is molarity (M), which shows the number of moles of solute per litre of solution (moles/Liter). Molarity is a unit of measurement that can be used to determine the volume of a solvent or the amount of a solute.

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