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Simple tricks to solve questions on cubes
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Ever faced problems in attempting commonly asked cube based questions in exams!! Chaitanya through this lesson helps you to visualize and find the answers to the different types of cube based questions. He supports the explanation to the two types of question on - cuts and identical cubes with simple formulas and tricks to give you the edge in managing your time.

Chaitanya K
Graduated from IIM A

U
Unacademy user
z me galat btaya gya hai
I am watching this lesson on windows 10 laptop and I can not see contribute button. I can see "follow" and "save". but no contribute button, kindly help me out.
It's formulating everything.Please give elaborative explanation.
Great Video Sir........keep going......
  1. COURSE:LOGICAL REASONING LESSON : CUBES Presented By: Chaitanya


  2. About Me . MBA from IIMA Electronics and Software Engineer - 2Years Teaching Experience : 3 Years Course Fees: CONTRIBUTE Follow me on Unacademy: https://unacademy.in/user/chaitanyaunacademy Electronics and Communication Engineer httpslunacademy.inuserchaitanyaunacademy


  3. Types of Questions Cuts and Identical pieces Volume = a3 Surface Area = 6a2 1 Cut Maximum Identical Pieces-2 2 Cuts Minimum Identical pieces = 3 Maximum Identical pieces 4 Edge-12 Logic: | | Cuts can be made in 1 direction only Minimum | Vertex = 8 identical pieces Always 1 more than the number of cuts made Cuts made along the length, breadth and height Maximum pieces Face 6


  4. Cuts made along L = a Cuts made along B b Cuts made along H = c Volume = a3 Surface Area = 6a2 Pieces along L = a+1 Pieces along B b+1 Pieces along H = c+1 Edge-12 Formula Maximum number of identical pieces- (a+1)(b+1)(c+1) Vertex = 8 Example If you make15 cuts on a cube, find the maximum number of identical pieces Distribution of cuts = (5,5,5) Max no. of identical pieces = (5+1)(5+1)(5+1) = 216 Face 6


  5. 16 cuts Distribution = (5,5,6) Max identical pieces (5+1) (5+1)(6+1) =252 Reverse Concept (Pieces given,find cuts Pieces = P Find factors of P *The deviation between the factors should be minimum P-a*b* Formula Minimum Cuts-(a-1)+(b-1)+(c-1) Volume = a3 Surface Area 6a2 Edge-12 Vertex = 8 Eq Pieces required = 100 100= 5*5*4 Cuts along length = 5-1-4 Cuts along breadth = 5-1-4 Cuts along height = 4-1-3 Minimum no of cuts = 4+4+3 = 11 Face=6