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Refrigeration Numericals - COP based (in Hindi)
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Numericals based on COP calculations and basic refrigeration system are discussed.

Gaurav Joshi
Mechanical Engineer. Secured AIR 5 in ESE & AIR 47 in GATE. Also cleared BARC,ONGC,ISRO. Worked for BARC, HITACHI.Guitar player & Vocalist

U
MPTET मे ग्रेड वन यानी उच्च माध्यमिक शिक्षक की पेडगोजी का सिलेबस उपलब्ध कराने का कष्ट करें।
nice lecture sir.....
nice video lectures sir
sir, in ques 3, we can also reduce one step. As we have calculated that the COP is less than 1, so we know that the work input must be greater than the heat leakage i.e. 30KW ,and there is only one option having value greater than 30 KW
kbc style sir g. :D
simply d best sir j
1. Refrigeration Basics (ESE-Questions) (For ESE AND GATE) GAURAV JOSHI

2. About me GAURAV JOSHI B. Tech in Mechanical Engineering (2010-14) Cleared ESE 2017 - AIR 5 Cleared GATE 2017 AIR 47 Worked For BARC in 2017 Taught Physics in Allen Career Institute and Aakash- Institute from 2014-16 Worked for Hitachi (Air- Conditioners) in 2014

3. Problems CESE Que 3) op iuto the celd chauber is sokhi. If th* achual coP .b plant is y' .b Max COP, Stora [AJ !.gokw [EJ 3.yok!

4. t. Max TH-TL (CoP) - a 42 ache 1o Max Win (CoP)ac* 46.So kw

5. Quet) AsserhuHt pump used for h ik is a nite advancement ewe the simple thate Reason: The t at puup is for more lonouicus in operation haw Juctric Wister ESE- 1a9sJ CcJ Arue ,R is false A is false, R is true

6. Sol In Keat Pum In Wlin Mar ns.

7. Thank You