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Basics of Refrigeration and Numerical Problems (in Hindi)
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In this lesson COP is discussed in detail. Basic numericals are also solved for better understanding.

Gaurav Joshi
Mechanical Engineer. Secured AIR 5 in ESE & AIR 47 in GATE. Also cleared BARC,ONGC,ISRO. Worked for BARC, HITACHI.Guitar player & Vocalist

Comments
(7)
U
Unacademy user
Hi Shoaib, Is this summary is sufficient because I see a lot more fact and figures are provided in the YOJANA? By the way you have done an awesome job for all UPSC-CSE aspirants. Thank You so much.
what is the heat capacity for R134A
sir is the temp of of refrigerent in evaporator wll be less than the room temp that is going to be to be colled..?? otherwise how it will absorb heat from the room ...??
Sir...........here what is 3600 ?????????????
Shiva Rajeswari
10 months ago
1hr= 3600secs, to convert unit
Thank you sir plz upload more lectures on Mechanical Engineering.
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