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Phy-XI-4-13 numerical on 2D motion
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Application of principles in two dimension motion specially vector addition and subtraction are explained in this lesson

State topper in school exams, selected in IIT Kharagpur, M.Sc., 30 yrs in teaching.

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1. PHYSICS for NEET and JEE Pradeep Kshetrapal Class XI Portion

2. Chapter 4- Motion in a Plane Numerical on 2-D motion Phy-XI-4-13

3. Q1. Rain is falling vertically with a speed of 30m/s . A woman rides a bicycle with a speed of 10m/s in the north to south direction in which direction she should hold the umbrella? Solution: velocity of rain is 30 m/s VR 30m/s

4. Given a woman is moving in a bicycle from north to south with a speed of 10m/s. So, 10m/s We want direction of relative velocity of rain with respect to the woman in the bicycle. When two objects are moving there comes a concept of relative velocity.

5. The direction of rain Umbrella with respect to bicycleV RC IS is R- . Here, VRc is the direction of velocity of the rain with respect to cycle. So, direction of umbrella is opposite to that.

6. Let 9 be the angle from the vertical with which the umbrella should be tilted. Umbrella tan =10 an-le)-18.43 . 30 RC 3 The woman should bend her umbrella by 18.43 in forward/ south direction.

7. Q2. A cyclist is riding with a speed 27 km/h As he approaches a circular turn on the road of radius 80m,he applies brakes and reduces his speed at a constant rate of 0.50 m/s every second. What is the magnitude and direction of the net acceleration of the cyclist on the circular turn?

8. Solution: aT V' dt dv acP 27km/h-15 m/s Given, tangential acceleration,a,--0.5ms-2 This is retardation.

9. We know that in circular motion there is one more acceleration is working on it i.e.,centripetal acceleration . cp V' dt dv acP

10. For angle between vectors is 90% then the resultant is T' aT et We know that 15 15 r 80 64 so, net acceleration is R='| (45)2+92= 0.86 ms-2