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Concept of Remainder Part 1

Q.1) Find remainder when 25A25 is divided by 24? Q.2) Find remainder when 25A25 is divided by 26? Same Question but Divisor different. Remainder? Any Idea!

Let's Learn the Concept If a number (N+1)A odd/even is divided by N Remainder is 1 If a number (N-1)A even is divided by N Remainder is 1 . If a number (N-1)A Odd is divided by N Remainder is N-1 . Ready to Solve the Question Let's see

Let's Solve Q.1) Find remainder when Q.2) Find remainder when 25 25 is divided by 24? 25A25 is divided by 26? Form (N+1)A odd divided Form: (N-1)Aodd divided by N by N Remainder is 1 Remainder is (N-1) i.e 25

Let's Learn some more Concepts . XAn - yAn is always divisible by (x-y) Q) 746n 6A6n, where n is any integer > 0, is (CAT 2002) divisible by a)13 b) 127 c)559 d) None of these Sol) Let's take n-1 so 7A6-6A6 div by (7-6) or 34342 -21642 div by 343-216 127 There Ans is 127

X^n-yAn is divisible by (x+y) when n is even Q.) The number (2A48-1) is exactly divisible by two numbers between 60 and 70.Numbers are a)63,65 b)63,67 c)61,65 d)65,67 Sol) 2448 64 8 So 6448-148 is exactly divisible by (64-1) and (64+1)

XAnyAn is divisible by (x+y)when n is odd Q) The remainder when 25A33 + 32A33 is a) 0 b) 1 c)4 d)9 Sol) Clearly the given expression will be divisible divided by 19, is by 57. Therefore on dividing by 19 remainder is 0

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Vishal Sharma

I am an engineer by education and teacher by choice.I have been training students for CAT exams for 16 years.I have worked with top brands l

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Chetan Bavaskar

a year ago

finally improved my score from 94/200 in Mock Test 1 to 123.44/200 in Mock test 2.....happy...:)

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