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13 lessons,
2h 39m
Concept of Remainder
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Learn the concept of Remainder and practice Real CAT questions

Vishal Sharma
I am an engineer by education and teacher by choice.I have been training students for CAT exams for 16 years.I have worked with top brands l

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  1. Faculty : Vishal Sharma More than 16 years of experience in CAT training Trained 10000+ students till date

  2. Concept of Remainder Part 1

  3. Q.1) Find remainder when 25A25 is divided by 24? Q.2) Find remainder when 25A25 is divided by 26? Same Question but Divisor different. Remainder? Any Idea!

  4. Let's Learn the Concept If a number (N+1)A odd/even is divided by N Remainder is 1 If a number (N-1)A even is divided by N Remainder is 1 . If a number (N-1)A Odd is divided by N Remainder is N-1 . Ready to Solve the Question Let's see

  5. Let's Solve Q.1) Find remainder when Q.2) Find remainder when 25 25 is divided by 24? 25A25 is divided by 26? Form (N+1)A odd divided Form: (N-1)Aodd divided by N by N Remainder is 1 Remainder is (N-1) i.e 25

  6. Let's Learn some more Concepts . XAn - yAn is always divisible by (x-y) Q) 746n 6A6n, where n is any integer > 0, is (CAT 2002) divisible by a)13 b) 127 c)559 d) None of these Sol) Let's take n-1 so 7A6-6A6 div by (7-6) or 34342 -21642 div by 343-216 127 There Ans is 127

  7. X^n-yAn is divisible by (x+y) when n is even Q.) The number (2A48-1) is exactly divisible by two numbers between 60 and 70.Numbers are a)63,65 b)63,67 c)61,65 d)65,67 Sol) 2448 64 8 So 6448-148 is exactly divisible by (64-1) and (64+1)

  8. XAnyAn is divisible by (x+y)when n is odd Q) The remainder when 25A33 + 32A33 is a) 0 b) 1 c)4 d)9 Sol) Clearly the given expression will be divisible divided by 19, is by 57. Therefore on dividing by 19 remainder is 0

  9. Thank You