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Answer: Let us assume the power as P. It is the rate at which the electrical circuit transfers energy per second.
Formula of power: P = IV
Or, P = I. IR (using Ohm’s Law)
Therefore, P = R. I2
or, P = V2/R … (i)
Here, V is the circuit’s potential difference while I stands for the amount of current.
R = V2/P (from equation i)
Therefore resistance is 2202 / 100 = 484 ohms.
Similarly for 110 V electric bulb, power consumed will be = V2/R or, 1102 /484 W
Therefore consumed power will be 25 W.