A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

Answer:- 14.14m

Explanation

In 40 seconds, the farmer covered a distance of 4*(10) = 40 metres.

The farmer’s average speed is 40 metres per forty seconds, which equals one metre.

Two minutes and 20 seconds can be written as (2 x 60) + 20=140 seconds.

The farmer’s total distance travelled during this time period is 1 metre * 140 metres, or 140 metres.

Using the formula 140m/40 = 3.5 laps, the total number of laps completed by the farmer will be.

As a result, the farmer’s total displacement will be equal to the length of the diagonal line connecting the square’s two corners.

When the Pythagorean theorem is used,

The diagonal length is given as follows:

√(102+102)= √200= 14.14m.