Answer: Magnification is reckoned as the increment in the size of the image produced by the spherical mirror in consideration of the object’s size.
The magnification is denoted by (m) and is the image height ratio to the object height.
The magnification (m), exhibited by a spherical mirror, can be expressed as:
m = H/H’
Where,
H is denoted as the image height, and H’ is denoted as the object height.
In the question, it is given as follows:
m = – 3 (real image)
(u) = – 10 cm
(v) = ?
We cognise that, m= -v/u
-3 = -v /-10
-3 = v/10
v = – 3 × 10
v = – 30 cm
Hence, the image is 30 cm outside of the concave mirror.