A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate (1) The maximum height to which it rises. (2) The total time it takes to return to the surface of the earth

Specified parameters 

• Ball(u) initial velocity = 49m/s.
• Balls velocity at (v) maximum height = 0.
• g = 9.8m/s2

To find out

1) The extreme altitude to which it will rise.

2) The entire time it covers coming back to the earth’s surface.

Answer

Let us assume the period is t for reaching the extreme height which is H.

Considering a formula,

2gH = v2 – u2

2 × (- 9.8) × H = 0 – (49)2

– 19.6 H = – 2401

H = 122.5 m

Now considering a formula,

v = u + g × t

0 = 49 + (- 9.8) × t

– 49 = – 9.8t

t = 5 sec

Response

(1) The maximum height to which the ball rises = 122.5 m

(2) The total time the ball takes to return to the surface of the earth = 5 + 5 = 10 sec.