Question & Answer » Mathematics Questions » Which of the following are APs? If they form an A.P. find the common difference d and write three more terms. (i) 2, 4, 8, 16 … (ii) 2, 5/2, 3, 7/2 …. (iii) -1.2, -3.2, -5.2, -7.2 … (iv) -10, – 6, – 2, 2 … (v) 3, 3 + √2, 3 + 2√2, 3 + 3√2 (vi) 0.2, 0.22, 0.222, 0.2222 …. (vii) 0, – 4, – 8, – 12 … (viii) -1/2, -1/2, -1/2, -1/2 …. (ix) 1, 3, 9, 27 … (x) a, 2a, 3a, 4a … (xi) a, a2, a3, a4 … (xii) √2, √8, √18, √32 … (xiii) √3, √6, √9, √12 … (xiv) 12, 32, 52, 72 … (xv) 12, 52, 72, 73 …

Which of the following are APs? If they form an A.P. find the common difference d and write three more terms. (i) 2, 4, 8, 16 … (ii) 2, 5/2, 3, 7/2 …. (iii) -1.2, -3.2, -5.2, -7.2 … (iv) -10, – 6, – 2, 2 … (v) 3, 3 + √2, 3 + 2√2, 3 + 3√2 (vi) 0.2, 0.22, 0.222, 0.2222 …. (vii) 0, – 4, – 8, – 12 … (viii) -1/2, -1/2, -1/2, -1/2 …. (ix) 1, 3, 9, 27 … (x) a, 2a, 3a, 4a … (xi) a, a2, a3, a4 … (xii) √2, √8, √18, √32 … (xiii) √3, √6, √9, √12 … (xiv) 12, 32, 52, 72 … (xv) 12, 52, 72, 73 …

Answer: (i) 2, 4, 8, 16 …  

This series is not an A.P.

 

(ii) 2, 5/2, 3, 7/2 …. 

 This is an A.P. series and its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = 5/2 – 2

=>    = 1/2 = 0.5

Therefore, d = 0.5

 

(iii) -1.2, -3.2, -5.2, -7.2 …

 This is an A.P. series and its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = -3.2 – (-1.2)

=>    = -2

Therefore, d = -2

 

(iv) -10, – 6, – 2, 2 …

This is an A.P. series and its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = -6 – (-10)

=>    = 4

Therefore, d = 4

 

(v) 3, 3 + √2, 3 + 2√2, 3 + 3√2

This is an A.P. series and its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = 3+√2 – 3

=>    = √2

Therefore, d = √2

 

(vi) 0.2, 0.22, 0.222, 0.2222 …. 

This series is not an A.P.

 

(vii) 0, – 4, – 8, – 12 …

This is an A.P. series and its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = -4 – 0

=>    = -4

Therefore, d = -4

 

(viii) -1/2, -1/2, -1/2, -1/2 ….

This is an A.P. series and its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = -1/2 – (-1/2)

=>    = 0

Therefore, d = 0

 

(ix) 1, 3, 9, 27 …

This series is not an A.P.

 

(x) a, 2a, 3a, 4a …

This is an A.P. series and its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = 2a – a

=>    = a

Therefore, d = a

(xi) a, a2, a3, a4

This is not an A.P. series

 

(xii) √2, √8, √18, √32 …

This is an A.P. series.

This series can be rearranged as: √2, 2√2, 3√2, 4√2

and hence its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = 2√2 – √2

=>    = √2

Therefore, d = √2

 

(xiii) √3, √6, √9, √12 …

This is not an A.P. series

 

(xiv) 12, 32, 52, 72 …

This is an A.P. series and its common difference d is:

=> d = an – an-1

=> d = a2 – a1

=>    = 32 – 12

=>    = 20

Therefore, d = 20

 

(xv) 12, 52, 72, 73 …

This is not an A.P. series