Find the zeros of the polynomial 6x² – 3 – 7x and verify the relationship between the zeros and the coefficients of the polynomial.

Answer: f(x) = 6x² – 7x – 3

To find the 0:

Let us put f(x) = 0

6x²– 7x – 3 = 0

⇒ 6x²– 9x + 2x – 3 = 0

⇒ 3x(2x – 3) + 1(2x – 3) = 0

⇒ (2x – 3)(3x + 1) = 0

⇒ 2x – 3 = 0

x = 3/2

⇒ 3x + 1 = 0

⇒ x = -1/3

For x = 3/2 and x = -1/3, it gives us two zeros.

As a result, the quadratic equation’s zeros are 3/2 and -1/3.

Now it’s time for verification.

− coefficient of x / coefficient of x2 = sum of zeros