Find the Sum of the First Five Multiples of 3

Answer: 45

Three, six, nine, twelve, and fifteen are the first five multiples of three.

The sum of 3 + 6 + 9 + 12 + 15 equals 45.

As a result, the total of the first five multiples of three equals 45.

3, 6, 9, 12, 15 are other viable options.

Here, n = 5, a = 3, and l = 15 are the values.

The sum of AP with the first term a and the last term l is:

(n/2)(a + l) = S

(3 + 15) = (5/2)

= (18/5) *(5/2)= 5*9=45

As a result, the required amount is 45.