Find the Smallest Number which when Increased by 17 is Exactly Divisible by both 520 and 468.

Answer:

To find the smallest number we have to first claim the LCM of 520 and 468.

520 = 2 22513

468 = 223313

Thus, LCM of 520 and 469 = 22233513

LCM of 520 and 469 = 4680

Redefining the statement, the smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468. 

That is, (LCM of 520 and 468) – 17 = 4663.

Thus, the smallest number which when increased by 17 is exactly divisible by both 520 and 468 is 4663.