Profile
Settings
Refer your friends
Sign out
Question: Find the integral of 1/x
Explanation
According to the fundamentals of calculus from the differential calculus, the integral of 1/x is as follows:
We know that 1/x is the derivative of the log(x); so
(d/dx) (log x) = 1/x (if x>0)
Applying the chain rule we get,
(d/dx) (log- x) = 1/x (if x<0)
Hence, we can say that log|x|is the integral of 1/x that covers both types of integers positive and negative.
