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Find the Integral of 1/x

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Question: Find the integral of 1/x

Explanation

According to the fundamentals of calculus from the differential calculus, the integral of 1/x is as follows:

We know that 1/x is the derivative of the log(x); so 

(d/dx) (log x) = 1/x            (if x>0)

Applying the chain rule we get, 

(d/dx) (log- x) = 1/x           (if x<0)

Hence, we can say that log|x|is the integral of 1/x that covers both types of integers positive and negative.