A long-Distance train is Scheduled to reach its Destination in 19 hours. After 10 Hours of Journey, due to Disruption of rail traffic, the train has to be stationed for 1 hour. If the Average Speed of the train is 100kmhr, at what speed should it travel to cover the distance in the same amount of time

Answer: The train’s median speed is indicated as 100 km/hr.

Thus, the complete distance must be accomplished in 19 hours.

Distance total equals 19 x 100 equals 1900 kilometres

Total distance travelled after 10 hours equals 10 x 100 equals 1000 kilometres

Distance to go equals (1900 – 1000) equals 900 kilometres

Because the train has been delayed by one hour,

Total time invested equals 10 + 1 equals 11 hours

If the remainder distance must be travelled in a very similar period of time, then the remaining time equals (19 – 11) equals 8 hr.

As a result, the needed speed equals (the remaining miles / remaining timeframe).

= (900 / 8) = 112.5 km/hr.