What is the Bond Order of NO and NO+

Answer : The bond order demonstrates the specific number of chemical bonds that are shown between the NO and NO⁺ a pair of atoms.

Despite this, the formula of the Bond Order can be described as half (½) of the distinction between (a-b) the number of electrons in bonding orbitals (a) and antibonding orbitals (b).

So, the formula of the bond order is given in the below as;

Bond order= ½ (a-b)

(1) NO⁺

Total electrons number in NO⁺ = 14.

You can calculate the Bond order of NO⁺ as the below given example. 

For instance, a = 10, b= 4

Bond order = ½ (10 – 4)

Bond order = ½ (6) = 3

Finally, the Bond order of NO⁺ is 3.

(2) NO

The NO antibonding electrons numbers are 5.

Its bond order is calculated as the below given example. 

Bond order = ½ [10 – 5]

Bond order = ½ [5] = 2.5