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Answer : The bond order demonstrates the specific number of chemical bonds that are shown between the NO and NO+ a pair of atoms.
Despite this, the formula of the Bond Order can be described as half (½) of the distinction between (a-b) the number of electrons in bonding orbitals (a) and antibonding orbitals (b).
So, the formula of the bond order is given in the below as;
Bond order= ½ (a-b)
(1) NO+
Total electrons number in NO+ = 14.
You can calculate the Bond order of NO+ as the below given example.
For instance, a = 10, b= 4
Bond order = ½ (10 – 4)
Bond order = ½ (6) = 3
Finally, the Bond order of NO+ is 3.
(2) NO
The NO antibonding electrons numbers are 5.
Its bond order is calculated as the below given example.
Bond order = ½ [10 – 5]
Bond order = ½ [5] = 2.5
