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Q. The structural formula of ethyne is
Ethyne:
The molecule formula for Ethyne – C2H2
The elements present in ethyne are carbon and hydrogen.
Atomic number of carbon – 6
Electronic configuration – 1s22s22p2
Excited electronic configuration of carbon 1s22s12px12py12pz1
Atomic number of hydrogen – 1
Electronic configuration of hydrogen – 1s1
Because there is only one hydrogen atom in the CH molecule, the 2s1and 2pz1 orbitals become hybridized. Each CH molecule will result in the formation of two hybridized sp orbitals, for a total of four sp hybridized orbitals.
During hybridisation, one sp orbital from each carbon overlaps with the 1s orbital of hydrogen, forming a C-C sigma bond, while the second sp orbital from each carbon overlaps with the 1s orbital of hydrogen, forming two C-H bonds.
In this structure, the carbon atom will have two half-filled 2p orbitals. These two pairs of p orbitals produce two pi bonds instead of participating in the hybridisation, leading to the formation of a triple bond.
Therefore, the structural formula of ethyne is as follows;
Important points to remember:
Because it has one sigma and two carbon-carbon pi bonds, the ethyne molecule is sp hybridised.
In ethyne, there is a triple bond between the two carbon atoms.
Each CH molecule produces two hybridized sp orbitals, for a total of four sp hybridized orbitals.
These two pairs of p orbitals produce two pi bonds instead of participating in the hybridisation, resulting in the development of a triple bond.
