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Structure of ICl2−
A. Trigonal
B. Octahedral
C. Square planar
D. Distorted trigonal pyramidal
Explanation of the present question is down below.
The VSEPR theory can, as far as we are aware, be used to determine the structure. According to the VSEPR theory, ICl2 possesses 7 + 2 + 1 electrons, which equals 10 total electrons. Because of this, we learn that the fundamental geometry consists of triangles and bipyramids (TBP).
As can be seen, there are only two bond pairs present, but there are three lone pair electrons. In this case, the lone pairs are located in an equatorial location, which reduces the amount of repulsion between them. Therefore, linearity may be inferred from geometry.
According to the structure of ICl2, also known as the iodine dichloride anion, In one plane, the iodine dichloride anion possesses three lone pairs, and these lone pairs are organized in the shape of a triangle around an atom in the center. Despite the fact that ICl2 is composed of three atoms lined up in a row in the z-plane.
As is well knowledge, the structure of ICl2 is known to be linear and to include a lone pair. I here possess seven electrons, and each of the two Cl atoms gives out two electrons, one of which has a negative charge. Therefore, the total of ten electrons in the system. Therefore, it becomes trigonal bipyramidal; nevertheless, because there are two and three lone pair electrons, it becomes linear in structure and has a hybridization of sp³d. Because of sp³d hybridization, we are aware that it does not have trigonal, octahedral, or square planar crystal structures.
As a result, choice D is the one to go with.
