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N1V1 = N2V2
Normality of HCL = 12N
Now,
N1 = 12N
N2 = 1N (Given)
V2 = 100 ml
V1 = ?
After putting the given values in the formula, we get
12 × V1 = 1 × 100
V1 = 100/12
V1 = 8.33
So, 8.33 mL HCl should be added to 100 L, to get a 1N HCI solution.