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Answer: A solution’s equivalent weight is calculated by dividing the solute’s molecular weight by its valence.
We must first determine the molecular weight of the various elements that make up the molecule.
Sodium, carbon and oxygen are the individual elements in Na2CO3
Sodium, Carbon and oxygen have molecular weights of 22, 12 and 16 respectively.
The molecular weight of Na2CO3 can be simply computed.
2 (Na) + (C) + 3(O)
= 2 (23) + (12) + 3(16) = 46 + 12 + 48 = 106.
The sulfuric acid Na2CO3‘s molecular mass is 106 g/mol.
Equivalent weight of Na2CO3
= 106/2
= 53 g/eq.