How Do You Write The Electron Configuration of Scandium

Answer: The scandium (Sc) electron configuration is written as 1s² 2s²2p⁶ 3s² 3p⁶ 3d¹ 4s².

Sub-energy levels are subdivided from atomic energy levels. Orbital levels are sub-energy levels. ‘l’ represents the sub energy levels. The range of values for ‘l’ is 0 to (n – 1). S, p, d, and f are the sub-energy levels. The value of ‘l’ for various energy levels is determined by-

• If n = 1, (n – 1) = (1–1) = 0 

           As a result, ‘l’ has an orbital number of 1; and the orbital is 1s. 

• If n = 2, (n – 1) = (2–1) = 1. 

As a result, ‘l’ has an orbital number of 2; and the orbital is 2s, 2p. 

• If n = 3, (n – 1) = (3–1) = 2. 

As a result, ‘l’ has an orbital number of 3; and the orbital is 3s, 3p, 3d. 

• If n = 4, (n – 1) = (4–1) = 3 

As a result, the orbital number of ‘l’ is 4; the orbitals are 4s, 4p, 4d, and 4f. 

• If n = 5, (n – 1) = (n – 5) = 4.

As a result, l = 0,1,2,3,4. The number of orbitals will be 5, however the electrons of all the elements in the periodic table can be arranged in 4s, 4p, 4d, and 4f in these four orbitals. These orbitals have electron retention capacities of s = 2, p = 6, d = 10, and f = 14. 

Scandium’s first two electrons enter the 1s orbital. A maximum of two electrons can be found in an s-orbital. As a result, the following two electrons are assigned to the 2s orbital. A maximum of six electrons can be found in the p-orbital. As a result, the next six electrons are assigned to the 2p orbital. The second orbit is now completely filled. As a result, the remaining electrons will be pushed into the third orbit. 

Then two electrons will reach the third orbit’s 3s orbital, followed by six electrons in the 3p orbital. The 3p orbital is currently completely filled. As a result, the following two electrons will enter the 4s orbital, whereas the last electron will enter the 3d orbital. As a result, the electron configuration of scandium(Sc) will be 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹ 4s².