Find the Oxidation Number of Cr in K2Cr2O7?

Answer: Two potassium cations and one dichromate anion make up potassium dichromate, an ionic compound. Tetrahedral coordination geometries surround the chromium atoms.

The oxidation state of potassium is +1, while the oxidation state of oxygen is -2.

So, potassium ions have a total charge of +1(2) = 2 , whereas oxygen ions have a charge of 2(7) = 14.

Let x be the chromium’s oxidation number.

As a result, we can express the equation as follows:

2+ x- 14 = 0

-12 + x = 0

x = 12

The oxidation number of two chromium atoms is thus +12

As a result, each chromium atom has an oxidation number of 12 / 2 = 6.

As a result, the Cr oxidation number in K₂Cr₂O₇ is +6.

As a result, potassium has an oxidation state of + 1, oxygen has an oxidation state of -2, and chromium has an oxidation state of + 6 in the molecule.